您可以创建匿名对象并将其序列化:
var sample = new Sample {
name = "Bob",
myclass = new MyClass {
p1 = "x",
p2 = "y"
}};
string json = JsonConvert.SerializeObject(new {
sample.name,
sample.myclass.p1,
sample.myclass.p2
});
结果
{"name":"Bob","p1":"x","p2":"y"}
但我建议您要么使用Sample
类的默认序列化,要么创建将序列化为您的格式的类(即将MyClass
属性移动到Sample
.
更新:您可以使用自定义转换器,它将对象展平并将所有内部对象属性序列化为顶级对象属性:
public class FlattenJsonConverter : JsonConverter
{
public override void WriteJson(JsonWriter writer, object value,
JsonSerializer serializer)
{
JToken t = JToken.FromObject(value);
if (t.Type != JTokenType.Object)
{
t.WriteTo(writer);
return;
}
JObject o = (JObject)t;
writer.WriteStartObject();
WriteJson(writer, o);
writer.WriteEndObject();
}
private void WriteJson(JsonWriter writer, JObject value)
{
foreach (var p in value.Properties())
{
if (p.Value is JObject)
WriteJson(writer, (JObject)p.Value);
else
p.WriteTo(writer);
}
}
public override object ReadJson(JsonReader reader, Type objectType,
object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override bool CanConvert(Type objectType)
{
return true; // works for any type
}
}
用法:
string json = JsonConvert.SerializeObject(sample, new FlattenJsonConverter());
或者,如果您只需要一种类型的这种行为,您可以简单地将匿名类型创建隐藏到自定义转换器中:
public class SampleJsonConverter : JsonConverter
{
public override void WriteJson(JsonWriter writer,
object value, JsonSerializer serializer)
{
Sample sample = (Sample)value;
JToken t = JToken.FromObject(new {
sample.name,
sample.myclass.p1,
sample.myclass.p2
});
t.WriteTo(writer);
}
public override object ReadJson(JsonReader reader, Type objectType,
object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override bool CanConvert(Type objectType)
{
return objectType == typeof(Sample);
}
}