我遇到了一个问题,这无疑是由于我的想法有缺陷,但我似乎无法解决这个问题。我有一个这样的结构:
typedef struct
{
ALLEGRO_BITMAP *bitmap;
char name[255];
signed int step; // How many frames to move per cycle. Negative values will cause the animation to reverse. Affects "current" frame only.
ANNE_SPRITE_CYCLES cycles;
ANNE_SPRITE_ANIMATIONS anim;
ANNE_SPRITE_FRAME current;
} ANNE_SPRITE;
如果我 malloc() 然后立即释放它,一切正常:
ANNE_SPRITE *sprite = malloc(sizeof(ANNE_SPRITE));
free(sprite);
printf("Haven't crashed yet, boss!");
但是,如果我在函数内部构建结构,如下所示:
ANNE_SPRITE anne_sprite_load(char sprite_name[]){
ANNE_SPRITE *sprite = malloc(sizeof(ANNE_SPRITE));
//Snipped: a bunch of code to populate the struct with data
return *sprite;
}
那么我不能在调用上下文中为爱或金钱释放结构:
ANNE_SPRITE test = anne_sprite_load("awesome_sprite");
free(test);
这会产生一个编译器错误——passing 'ANNE_SPRITE' to parameter of incompatible type 'void *'
事实上,我是——但我不知道如何将这个变量巧妙地转换为 free() 准备使用的格式。