regex - Regex - find a string and jump immediately to the next line

Question

For instance I am looking for something in a bigger text file - very simple for example a string of three digits with \d{3} . What I want to do is: when notepad++/textpad has found the first matching string in a line (and has replaced it with something else) it should jump immediately into the next line.

How can I accomplish that?

I tried \r\n , but in this case textpad finds not the first string with three digits in the line, but always the last. And notepad++ doesn't find anything at all.

I cannot use ^ either because there are some random words (one, two, three or even foru or five) before the digits I try to find and replace.

Thanks for any help.

Answer 1

为此，您必须将所有剩余的行包含到匹配的模式中。

例如，假设您搜索\d{3}并拥有以下数据：

qweqwe 123 rrr 445
test tetst
41 423 456

搜索：\d{3}(.*$)

替换：REPLACEMENT$1

会给你以下结果：

qweqwe REPLACEMENT rrr 445
test tetst
41 REPLACEMENT 456

如果您没有包含剩余的行 ( .*)，结果将是：

qweqwe REPLACEMENT rrr REPLACEMENT
test tetst
41 REPLACEMENT REPLACEMENT

在 Notepad++ 中，要使其工作，您必须取消选中“.matches newline”选项。