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我正在尝试为持久性类正确设置junit测试，即使我得到“绿色条”，我也担心几件事。当我在调试器中运行测试文件时，我可以看到 testList() 所有对象都按预期加载，如果任何一个有孩子，它们也会被加载。

For testList(), after I do...
instance.update(sg);
List <SettingsGroup> sl = instance.list();

...我在调试器（最后的屏幕截图）中看到未加载子级。

更新元素并将其取回以验证更新是否发生的正确方法是什么？现在我正在做类似的事情

instance.update(sg);
List <SettingsGroup> sl = instance.list();

...但我不确定。

当我尝试 testDelete() 时，元素列表的大小与删除之前相同，这让我感到奇怪。

当试图研究休眠测试时，我遇到了很多简单的例子，但我还没有得到如何正确设置、拆除和任何会话/事务管理。

我与这个类对应的表有 5 个“硬编码”行，所以我很确定“读取”调用。

测试班

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration( locations = {"applicationContext.xml"})
@Transactional
public class SettingGroupDaoTest extends AbstractJUnit4SpringContextTests {

    public SettingGroupDaoTest(){}
    SettingGroupDao instance;

    @BeforeClass
    public static void setUpClass() throws Exception {}

    @AfterClass
    public static void tearDownClass() throws Exception {}

    @Before
    public void setUp()   {
        Configuration c  = HibernateConfiguration.getHibernateConfiguration()
                .configuration(SettingsGroup.class);

        SessionFactory sessionFactory = c.buildSessionFactory();
        instance = new SettingGroupDao();
        instance.setSessionFactory( sessionFactory );
    }

    @Test
    public void testList() throws Exception {
        SettingsGroup sq = instance.get(1);
        SettingsGroup s1 = sq.getChildren().get(0);
        System.out.println( "children index 2 name: " + s1.getName() );
        System.out.println( "2nd element of children: " + sq.getChildren().get(1).getName() );
    }

    @Test
    public void testUpdate() throws Exception{
        SettingsGroup sg = instance.get(1);
        sg.setName("Updated Name of Setting Group");
        instance.update(sg);
        List <SettingsGroup> sl = instance.list();
        Hibernate.initialize( instance.list() );
        System.out.println( "UPDATED Settings Group Name: " + sg.getName() );
    }

    @Test
    public void testDelete() throws Exception{
        instance.delete( 0 );
        int s = instance.list().size();
        System.out.println( "Size after delete: " + s );
    }
}

为以上测试配置：

public class HibernateConfiguration {
    private HibernateConfiguration(){}
    public Configuration configuration( java.lang.Class clazz ) {
        Configuration c = new Configuration();
        c.setProperty(Environment.DRIVER, "org.postgresql.Driver");
        c.setProperty(Environment.URL, "jdbc:postgresql://localhost/###");
        c.setProperty(Environment.USER, "postgres");
        c.setProperty(Environment.PASS, "####");
        c.setProperty(Environment.DIALECT, "org.hibernate.dialect.PostgreSQLDialect");
        c.setProperty(Environment.AUTOCOMMIT, "true"); //"true");
        c.addClass( clazz );
        return c;
    }
    public static HibernateConfiguration getHibernateConfiguration(){
        return new HibernateConfiguration();
    }
}

域类：

@Entity
@SequenceGenerator(name = "settings_group_id_seq", sequenceName = "settings_group_id_seq")
@Cache(usage= CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@Table(name="settings_group")
public class SettingsGroup implements Serializable, DomainObject {

    private int id;
    private String name;
    private String code;

    private List<SettingsGroup> children = new LinkedList<SettingsGroup>();

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO, generator = "settings_group_id_seq")
    @Column(name = "id", insertable = false)
    public int getId() {return id;}

    public void setId(int id) {this.id = id;}

    @Column(name = "name")
    public String getName() {return name;}

    public void setName(String name) {this.name = name;}

    @Column( name = "code")
    public String getCode() {return code; }

    public void setCode(String code) {this.code = code;}


    @OneToMany( fetch = FetchType.EAGER)
    @JoinColumn( name = "parent_id")
    @OrderColumn
    public List<SettingsGroup> getChildren() {return children;}

    public void setChildren(List<SettingsGroup> children) {this.children = children;}
}

在此处输入图像描述

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1 回答 1

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一些想法......你正在做的实际上是一个集成测试，因为它需要一个数据库。其次，不是肯定的，但是您是否必须先提交更新才能成功查询更新的行？

于 2013-02-01T20:24:42.547 回答