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我浏览了论坛，找不到完全符合我的问题的任何内容。此查询应该为员工添加定期假期。如果我排除 PL_ID 变量并且只有一个没有主键的表，则代码会添加在 case 语句中定义的正确日期假期，这是在测试表上，但需要添加到具有超过 25,000 个条目的表中。

该表包括 PL_ID、Log_Date、Out_Time、In_Time

我目前有这个代码：

DECLARE @StartDate DateTime
DECLARE @EndDate DateTime
DECLARE @DateVar DateTime
DECLARE @PL_ID int

SET @StartDate = '1/10/2012'
SET @EndDate = '1/11/2012'
SET @DateVar = @StartDate
SET @PL_ID = 0

WHILE @DateVar <= @EndDate

BEGIN 
 INSERT INTO Logger_test2(PL_ID,Log_Date,In_Time,Out_Time)
 SELECT @PL_ID,@DateVar,
        CASE WHEN DATENAME(dw,@DateVar) = 'Thursday' THEN '9'
             WHEN DATENAME(dw,@DateVar) = 'Monday' THEN '12'
         END AS In_Time,
        CASE WHEN DATENAME(dw,@DateVar) = 'Thursday' THEN 'After 5'
             WHEN DATENAME(dw,@DateVar) = 'Monday' THEN 'After 5'
         END AS Out_Time      
  WHERE DATENAME(dw,@DateVar) IN ('Thursday','Monday')

 SET @DateVar = DATEADD(d,1,@DateVar)
 UPDATE Logger_test2 set @PL_ID = PL_ID = @PL_ID +1
 END

使用此代码，它只会在具有最大 PL_ID 的表中添加一行，但我需要它为每个条目创建一个新 ID，抱歉，它有点模糊。真的很感谢你的帮助！

现在离得到它更近了！但是，如果我将日期更改为下个月，则会出现重复的键错误：消息 2627，级别 14，状态 1，第 15 行违反主键约束“PK_Logger_test2”。无法在对象“dbo.Logger_test2”中插入重复键。重复键值为 (4) - 是否有另一种方法可以避免插入重复键？

已解决：这是完整的代码:)，很有魅力，让我的生活更轻松！只需更改用户ID，即可输入每个人预定的明年假期：

DECLARE @StartDate DateTime
DECLARE @EndDate DateTime
DECLARE @DateVar DateTime
DECLARE @PL_ID int
DECLARE @User_ID int
DECLARE @Reason nvarchar(50)
DECLARE @Details nvarchar (500)

SET @StartDate = '30/09/2012'
SET @EndDate = '24/12/2012'
SET @DateVar = @StartDate
SET @User_ID = 55
SET @Reason = 'Day off'
SET @Details = 'Day off' 

--SET @PL_ID = 0
SELECT @PL_ID = max(PL_ID) from People_Logger

WHILE @DateVar <= @EndDate

BEGIN
 select @PL_ID = @PL_ID +1
 SET IDENTITY_INSERT dbo.People_logger ON;
 INSERT INTO People_Logger(PL_ID,LOG_Date,User_ID,Reason,Details,In_Time,Out_Time)
 SELECT @PL_ID,@DateVar,@User_ID,@Reason,@Details,
        CASE WHEN DATENAME(dw,@DateVar) = 'Thursday' THEN 'After 5'
             WHEN DATENAME(dw,@DateVar) = 'Friday' THEN 'After 5'
         END AS In_Time,
        CASE WHEN DATENAME(dw,@DateVar) = 'Thursday' THEN '9'
             WHEN DATENAME(dw,@DateVar) = 'Friday' THEN '9'
         END AS Out_Time
  WHERE DATENAME(dw,@DateVar) IN ('Thursday','Friday')
SET IDENTITY_INSERT dbo.People_Logger OFF; 
 SET @DateVar = DATEADD(d,1,@DateVar)
END
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2 回答 2

1

好的，我认为您只需要在插入之前增加变量的值。像这样

WHILE @DateVar <= @EndDate
BEGIN

  select @PL_ID = @PL_ID + 1

  INSERT INTO Logger_test2(PL_ID,Log_Date,In_Time,Out_Time)
  SELECT @PL_ID,@DateVar,
  etc etc

  Set @DateVar= DATEADD(d,1,@DateVar)
  -- NO Update statement
END
于 2012-09-24T11:54:51.413 回答
0 
DECLARE @StartDate DateTime
DECLARE @EndDate DateTime
DECLARE @DateVar DateTime
DECLARE @PL_ID int

SET @StartDate = '1/10/2012'
SET @EndDate = '1/11/2012'
SET @DateVar = @StartDate
SET @PL_ID = 0

WHILE @DateVar <= @EndDate

BEGIN 
 INSERT INTO Logger_test2(PL_ID,Log_Date,In_Time,Out_Time)
 SELECT @PL_ID,@DateVar,
        CASE WHEN DATENAME(dw,@DateVar) = 'Thursday' THEN '9'
             WHEN DATENAME(dw,@DateVar) = 'Monday' THEN '12'
         END AS In_Time,
        CASE WHEN DATENAME(dw,@DateVar) = 'Thursday' THEN 'After 5'
             WHEN DATENAME(dw,@DateVar) = 'Monday' THEN 'After 5'
         END AS Out_Time      
  WHERE DATENAME(dw,@DateVar) IN ('Thursday','Monday')

 SET @DateVar = DATEADD(d,1,@DateVar)
 SET @PL_ID = @PL_ID +1
 END
于 2012-09-24T11:59:33.807 回答