ruby - 如何在Ruby中以特定方式组合两个数组数组

Question

假设我有这两个数组数组：

a = [[1],[2],[3]]
b = [[4],[5],[6]]

有没有一个选项可以让我像这样组合它们：

a.combined_somehow(b) == [[1,4],[2,5],[3,6]]

因为我希望它防止我在内部数组中重复。我的意思是，如果是：

a = [[1],[2],[3]]
b = [[1],[5],[3]]

输出将是：[[1],[2,5],[3]]

Answer 1

a = [[1],[2],[3]]
b = [[4],[5],[6]]

a.flatten.zip(b.flatten).map(&:uniq) # => [[1, 4], [2, 5], [3, 6]] 

b = [[1],[5],[3]]
a.flatten.zip(b.flatten).map(&:uniq) # => [[1], [2, 5], [3]] 

Answer 2

require 'pp'

a = [[1],[2],[3]]
b = [[1],[5],[3]]

def combine( a, b )
  [ a.flatten, b.flatten ].transpose.map(&:uniq)
end

pp combine( a, b )

输出

[[1], [2, 5], [3]]

Answer 3

在我看来只是感觉有点像Rubyish：

a = [[1],[2],[3]]
b = [[4],[5],[6]]

p a.zip(b).map(&:flatten) #=> [[1, 4], [2, 5], [3, 6]]

a = [[1],[2],[3]]
b = [[1],[5],[3]]

p a.zip(b).map{|x|x.flatten.uniq} #=> [[1], [2, 5], [3]]

Answer 4

我会如下：

a = [[1],[2],[3]]
b = [[4],[5],[6]]
a.map.with_index{|e,i| e | b[i]}
# => [[1, 4], [2, 5], [3, 6]]

a = [[1],[2],[3]]
b = [[4],[2],[6]]
a.map.with_index{|e,i| e | b[i]}
# => [[1, 4], [2], [3, 6]]