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我有一个表 EventLogs 记录给定事件的详细信息，例如事件的日期和费用。

+------+----------+---------------------------+-------------------+
| id   | place_id | start_at                  | total_fee_pennies |
+------+----------+---------------------------+-------------------+
| 4242 | 40       | 2013-10-20 19:00:00 +0100 | 8700              |
| 4288 | 48       | 2013-10-22 20:00:00 +0100 | 8000              |
| 4228 | 141      | 2013-10-17 19:30:00 +0100 | 20000             |
| 4232 | 19       | 2013-10-20 19:30:00 +0100 | 8000              |
| 4239 | 5        | 2013-10-20 19:30:00 +0100 | 6800              |
| 4269 | 6        | 2013-10-20 20:00:00 +0100 | 7000              |
| 4234 | 98       | 2013-10-20 20:00:00 +0100 | 6900              |

我希望能够按周汇总这些数据总费用，我相信这是一个 PIVOT？

所以我会为给定的月份选择它们：

"SELECT \"event_logs\".* FROM \"event_logs\"  WHERE (event_logs.start_at BETWEEN '2013-10-01' AND '2013-10-31')"

然后以某种方式将它们按不同的 place_id 和使用 start_at （通常一个月 5 周？）按周汇总，以及每周的总费用。

place_id，第 1 周，第 2 周，...

但我不知道该怎么做？

4

1 回答 1

2

在这里您可以找到如何提取周数。然后在 CASE 语句中使用周数

SQLFiddle 演示

WITH T AS
(
SELECT
EventLogs.*
,
extract(week from start_at) - 
extract(week from date_trunc('month', start_at)) + 1 as WeekNo


 FROM EventLogs  
WHERE (start_at BETWEEN '2013-10-01' AND '2013-10-31')
)

SELECT
place_id,
SUM(CASE WHEN WeekNo=1 THEN total_fee_pennies ELSE 0 END) as Week_1,
SUM(CASE WHEN WeekNo=2 THEN total_fee_pennies ELSE 0 END) as Week_2,
SUM(CASE WHEN WeekNo=3 THEN total_fee_pennies ELSE 0 END) as Week_3,
SUM(CASE WHEN WeekNo=4 THEN total_fee_pennies ELSE 0 END) as Week_4,
SUM(CASE WHEN WeekNo=5 THEN total_fee_pennies ELSE 0 END) as Week_5

from T

GROUP BY place_id
于 2013-10-31T14:58:09.970 回答