mysql - SQL 语句 - 选择此查询的逆

Question

我有这个查询，我想选择该选择的倒数。

SELECT Guide.id FROM Guide
INNER JOIN GuideAvailability ON Guide.id = GuideAvailability.guideId
WHERE GuideAvailability.startDate IN (1377946800)
GROUP BY GuideAvailability.guideId
HAVING COUNT(DISTINCT GuideAvailability.id) = 1

有没有简单的方法来解决我的问题？

Answer 1

只需使用此查询：

SELECT * 
     FROM Guide where id NOT IN (
       SELECT Guide.id 
         FROM Guide
         INNER JOIN GuideAvailability ON Guide.id = GuideAvailability.guideId
         WHERE GuideAvailability.startDate IN (1377946800) 
         GROUP BY GuideAvailability.guideId 
         HAVING COUNT(DISTINCT GuideAvailability.id) = 1
      )

Answer 2

可能是你在找这个

SELECT Guide.id FROM Guide
INNER JOIN GuideAvailability ON Guide.id = GuideAvailability.guideId
WHERE GuideAvailability.startDate NOT IN (1377946800) GROUP BY GuideAvailability.guideId HAVING COUNT(DISTINCT GuideAvailability.id) <> 1

Answer 3

你可以翻转布尔值。;)

当我有大量 where 过滤器并且有一组特定的排除过滤器时，我会这样做。我把它们写在箱子里，然后=1排除并=0找到我排除的东西。

SELECT Guide.id FROM Guide
INNER JOIN GuideAvailability ON Guide.id = GuideAvailability.guideId
WHERE ( case when GuideAvailability.startDate IN (1377946800) then 1 else 0 end) = 0
GROUP BY GuideAvailability.guideId
HAVING COUNT(DISTINCT GuideAvailability.id) = 1