ios - iOS：在for循环中将消息传递给不同的标签

Question

我在视图控制器中有六个标签，我在 for 循环中得到六个字符串，如下所示。

for(NSDictionary *dictionary in array)
{
     NSString *name = dictionary[@"Name"];
     NSLog(@"Name = %@ \n", name);
}

每当我在日志中获得一个名称时，我想将该名称以不同的标签（其中六个）发送到视图控制器。

如何将名称对象/消息传递给标签？您为每次迭代获得不同的名称/结果，并将这些迭代值传递给标签

在 for 循环中获取第一个名称，发布到标签 1。

在 for 循环中获取第二个名称，发布到标签 2 等等..

Answer 1

NSArray *lbls = [[NSArray alloc] initWithObjects:lbl1, lbl2, lbl3, lbl4, lbl5, lbl6, nil];

int i=0;
for(NSDictionary *dictionary in array)
{
     UILabel *lbl = (UILabel *)[lbls objectAtIndex:i++];
     [lbl setText:dictionary[@"Name"];
}

Answer 2

您可以创建名称到相应UILabel元素的映射：

你的类.h：

@interface YourClass : UIViewController {
    NSMutableDictionary *_labelMap;
    IBOutlet UILabel *_label1;   // Connected in IB
    IBOutlet UILabel *_label2;   // Connected in IB
    IBOutlet UILabel *_label3;   // Connected in IB
    IBOutlet UILabel *_label4;   // Connected in IB
    IBOutlet UILabel *_label5;   // Connected in IB
    IBOutlet UILabel *_label6;   // Connected in IB
}

...

你的班级.m：

@implementation YourClass {

- (void)viewDidLoad {
    // Not done in init, as you need the labels to be connected once the NIB is loaded
    _labelMap = [[NSMutableDictionary alloc] init];
    _labelMap[@"Name1"] = _label1;
    _labelMap[@"Name2"] = _label2;
    _labelMap[@"Name3"] = _label3;
    _labelMap[@"Name4"] = _label4;
    _labelMap[@"Name5"] = _label5;
    _labelMap[@"Name6"] = _label6;
    ...
}

- (void)yourMethod {
    for(NSDictionary *dictionary in array)
    {
        NSString *name = dictionary[@"Name"];
        NSLog(@"Name = %@", name);    // Don't need to add newline!
        UILabel *field = _labelMap[name];
        field.text = name;
    }
}