我需要使用 Python 执行某种类型的预测/建议。
例如，假设我们有多个列表
alphabet = ["a", "b", "c"]
other_alphabet = ["a", "b", "d"]
another_alphabet = ["a", "b", "c"]
还有一个目前正在建设的字母表
current_alphabet = ["a", "b", ...]
在 3 个字母中的 2 个中，后面的字母"a", "b"是"c"，所以我希望代码预测/建议current_alphabet在下一个字母"a", "b"中是"c"（概率为 66%）
我认为这项任务比看起来要复杂一些。
有什么建议可以实现吗？也许类似的东西可以在这个过程中有所帮助？
import itertools
alphabet = ["a", "b", "c"]
other_alphabet = ["a", "b", "d"]
another_alphabet = ["a", "b", "c"]
# here we take the nth char of each alphabet that is used as prediction
# (this position is indicated by the number of the currently entered char)
# zip takes the lists, and well, zips :) them, it means it creates new lists, so every
# first elements end up together, second elemends are together and so on.
# as far as current position you have to track it when user enters data (you have to
# know which (first, second, tenth) letter user is entering
current_position=1
letters = zip(alphabet,other_alphabet, another_alphabet)[current_position]
letters = list(letters)
letters.sort()
print 'letters at current position', letters
# here we group all occurences of the same letters,
letter_groups = itertools.groupby(letters, key=lambda x: x[0])
# here we count the number of occurences of each letter
# from the alphabets, and divide it by the lenght
# of the list of letters
letter_probabilities = [[a[0], sum (1 for _ in a[1])/float(len(letters))] for a in letter_groups]
print 'letter probablilities at the current postion ', letter_probabilities
上面的代码产生以下输出：
letters at current position ['c', 'c', 'd']
letter probablilities at the current postion [['c', 0.6666666666666666], ['d', 0.3333333333333333]]