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$user=mysql_fetch_array(mysql_query("select * from tb_user where user_login_id='".$_SESSION['SEEKER_ID']."'"));
$skill=$user['user_skills_id'];

$employerjobs=mysql_query("select * from tb_job where job_keyskills like '%$skill%' ORDER BY `job_id` DESC limit 10");
$countjobs=mysql_num_rows($employerjobs);

I have two table user and employee. have keep user key skill in $skill variable (php,mysl); and want to fetch from emplyee table

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1 回答 1

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我猜你需要对你的$skill变量使用连接,就像你对 所做的那样$_SESSION['SEEKER_ID'],这样脚本处理器就会知道你想要使用变量值而不是它的名称。

我不确定,但是您是否尝试过:

$employerjobs=mysql_query("select * from tb_job where job_keyskills like %'".$skill."'% ORDER BY `job_id` DESC limit 10");
于 2013-10-26T07:56:05.147 回答