sql-server-2008-r2 - 获取具有同一个表的两个外键的表的结果

Question

我有两个表，假设表“友谊”与列 f1、f2 和“人”与列 p_id、p_name。

友谊：=>

f1    f2
--------
01    10
02    11
03    12

人：=>

p_id  p_name
------------
01    Vijay
02    Ajay
03    Gaurav
10    Sunny
11    Amit
12    Sandeep

我想要这个表这样的结果

结果表应该是：=>

f1  f1_name  f2  f2_name
------------------------
01  Vijay    10   Sunny
02  Ajay     11   Amit
03  Gaurav   12   Sandeep

我尝试使用联合两个表，但找不到准确的结果

Answer 1

SELECT a.p_id f1, a.p_name f1_name, b.p_id f2, b.p_name f2_name FROM People a JOIN friendship f ON (f.f1 = a.p_id) JOIN People b ON (f.f2 = b.p_id)

Answer 2

我认为这可以解决您的问题。

select a.f1, c.p_name, b.f2, c.p_name
(select * from tablea) as a,// which have f1 and f2 columns
(select * from tablea) as b,
(select * from people) as c 
where a.f1=c.p_id and b.f2=c.p_id

Answer 3

你需要加入这个

select f1,  p.p_name as f1_name , f2, p1.p_name f2_name
from firendship as f
inner join People as p on f.f1=p.p_id
inner join People as p1 on f.f2=p1.p_id