我正在尝试将我的输出列表打印到一个文件中,作为下面的输出,但它一直给我错误。
样本输入
0
2
5
12
32
64
241
样本输入的 position.dat 的内容
[1, 0]
[0, 2]
[-4, -4]
[-64, 0]
[65536, 0]
[4294967296, 0]
[1329227995784915872903807060280344576, 1329227995784915872903807060280344576]
这是我的代码:
infile = open("position.dat", "w")
def B(n):
direction=[[1,0],[0,1],[-1,0],[0,-1]] #right, up, left, down
start=[0,0]
x=start[0]
y=start[1]
if n>50000:
return "Do not enter input that is larger than 50000"
elif n==0: #base case
return [1, 0]
elif n==1:
return [1, 1]
elif n%2==0 and n%4!=0: #digit start from n=2 and every 4th n digit
x=0 # start from second digit (n) x=0 for every 4th digit
y=((-4)**(n//4))*2
elif n%4==0: #print out every 4 digits n
y=0 #every 4digit of y will be 0 start from n=0
x=(-4)**(n//4) #the pattern for every 4th digits
elif n>3 and n%2 !=0 and n%4==1: #start from n=1 and for every 4th digit
x=(-4)**(n//4)
y=(-4)**(n//4)
elif n%4==3 and n%2 != 0: #start from n=3
y=((-4)**(n//4))*2
x=((-4)**(n//4))*-2
return [int(x),int(y)] #return result
print(B(0)) # print the input onto python shell
print(B(2))
print(B(5))
print(B(12))
print(B(32))
print(B(64))
print(B(241))
print(B(1251))
#Please also input the integers below for printing it on the the file
infile.write(B(0)+'\n') # these keep giving me error
infile.write(B(2)+'\n')
infile.close()
是否可以将列表打印到带括号的文件上?