2

假设我的 Neo4J 数据库中有 3 部电影:

CREATE (interpreter:Movie {title: 'The Interpreter', year : 2005})
CREATE (dogville:Movie {title: 'Dogville', year : 2003})
CREATE (railwayMan:Movie {title: 'The Railway Man', year : 2013})

还有用户:

CREATE (maciej:Person {name: 'Maciej Ziarko', birthYear: 1989})

谁给电影评分:

CREATE (maciej)-[:RATED {stars : 4, comment : "I liked that movie!" }]->(interpreter);

使用 Cypher 很容易找到特定用户评分的电影

MATCH (person:Person)-[:RATED]->(movie:Movie)
WHERE person.name = 'Maciej Ziarko'
RETURN movie.title

结果:

+-------------------+
| movie.title       |
+-------------------+
| "The Interpreter" |
+-------------------+
1 row

但是我怎样才能找到尚未被特定用户评分的电影

4

2 回答 2

4

你可能会使用类似的东西:

MATCH (m:Movie) WHERE NOT (m)<-[:RATED]-() return m.title

WHERE您可以使用 过滤不存在​​的路径NOT时,请参阅http://docs.neo4j.org/chunked/milestone/query-where.html#where-filter-on-patterns-using-not

于 2013-10-23T14:19:46.703 回答
0

阅读斯特凡的回答后我做了什么:

MATCH (movie:Movie), (person:Person)
WHERE person.name = 'Maciej Ziarko' 
     AND (NOT (movie:Movie)<-[:RATED]-(person:Person))
RETURN movie.title

结果:

+-------------------+
| movie.title       |
+-------------------+
| "Dogville"        |
| "The Railway Man" |
+-------------------+
2 rows
于 2013-10-23T14:29:52.570 回答