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我正在制作一个有关卡的游戏，我正在寻找一种比较 2 次的方法。第一次是玩家完成关卡所需的时间第二次是我选择的时间。如果第一次小于第二次，则获得一星，如果高于第二次，则不获得一星。正如您在下面的代码中所见，我已将 2 次存储在 NSDates 中。我使用 NSComparisonResult 来比较结果。我的问题是 NSComparisonResult Result1 = 4294967295 而不是 NSOrderedDescending 或类似的东西。

    NSDate *currentDate = [NSDate date];
    NSTimeInterval timeInterval = [currentDate timeIntervalSinceDate:self.startDate];
    NSDate *timerDate = [NSDate dateWithTimeIntervalSince1970:timeInterval];

    NSComparisonResult result1;
    NSComparisonResult result2;
    NSComparisonResult result3;
    // Create a date formatter
    NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
    [dateFormatter setDateFormat:@"mm:ss.SSS"];
    [dateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0.0]];

    //has three possible values: NSOrderedSame,NSOrderedDescending, NSOrderedAscending
    NSDate *level1ThreeStarRequirement = [dateFormatter dateFromString:@"00:01.500"];
    NSDate *level1TwoStarRequirement = [dateFormatter dateFromString:@"00:02.500"];
    NSDate *level1OneStarRequirement = [dateFormatter dateFromString:@"00:02.500"];

    result1 = [timerDate compare:level1ThreeStarRequirement]; // comparing two dates
    result2 = [timerDate compare:level1TwoStarRequirement];
    result3 = [timerDate compare:level1OneStarRequirement];
    if (result1 == NSOrderedAscending){
        self.star1.image = [UIImage imageNamed:@"star1.png"];
        self.star2.image = [UIImage imageNamed:@"star2.png"];
        self.star3.image = [UIImage imageNamed:@"star3.png"];
    }
    if (result2 == NSOrderedAscending){
        self.star1.image = [UIImage imageNamed:@"star1.png"];
        self.star2.image = [UIImage imageNamed:@"star2.png"];
        self.star3.image = [UIImage imageNamed:@"noStar.png"];

    }
    if (result3 == NSOrderedDescending){
        self.star1.image = [UIImage imageNamed:@"star1.png"];
        self.star2.image = [UIImage imageNamed:@"noStar.png"];
        self.star3.image = [UIImage imageNamed:@"noStar.png"];
    }

谢谢马蒂斯

4

1 回答 1

1

为什么不使用以下内置功能之一比较日期NSDate

– timeIntervalSinceDate:
– timeIntervalSinceNow
+ timeIntervalSinceReferenceDate
– timeIntervalSinceReferenceDate
– timeIntervalSince1970

这将以秒为单位为您提供一个值。那么您的result1etc 不应该是一些错误的数字，您可以直接将时间相互比较并像这样订购它们

于 2013-06-24T12:57:45.610 回答