2

我正在关注本教程:http ://www.raywenderlich.com/13160/using-the-google-places-api-with-mapkit ,但由于某种原因我的应用程序正在返回:

谷歌数据:( )

这是我的 .h 文件:

#import <UIKit/UIKit.h>
#import <MapKit/MapKit.h>
#import <CoreLocation/CoreLocation.h>

#define kBgQueue dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0)

#define kGOOGLE_API_KEY @"API PLACED HERE, LEFT BLANK FOR STACKOVERFLOW"

@interface ViewController : UIViewController <MKMapViewDelegate,     CLLocationManagerDelegate>
{
CLLocationManager *locationManager;
CLLocationCoordinate2D currentCentre;
int currenDist;
}

@property (strong, nonatomic) IBOutlet MKMapView *mapView;
@end

和我的实现文件:

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

- (void)viewDidLoad
{
[super viewDidLoad];

// Do any additional setup after loading the view, typically from a nib.

//Make this controller the delegate for the map view.
self.mapView.delegate = self;

// Ensure that you can view your own location in the map view.
[self.mapView setShowsUserLocation:YES];

//Instantiate a location object.
locationManager = [[CLLocationManager alloc] init];

//Make this controller the delegate for the location manager.
[locationManager setDelegate:self];

//Set some parameters for the location object.
[locationManager setDistanceFilter:kCLDistanceFilterNone];
[locationManager setDesiredAccuracy:kCLLocationAccuracyBest];
}

- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
- (IBAction)toolBarButtonPress:(UIBarButtonItem *)sender {
UIBarButtonItem *button = (UIBarButtonItem *)sender;
NSString *buttonTitle = [button.title lowercaseString];
[self queryGooglePlaces:buttonTitle];

}

-(void) queryGooglePlaces: (NSString *) googleType {
NSString *url = [NSString     stringWithFormat:@"https://maps.googleapis.com/maps/api/place/search/json?  location=%f,%f&radius=%@&types=%@&sensor=true&key=%@", currentCentre.latitude, currentCentre.longitude, [NSString stringWithFormat:@"%i", currenDist], googleType,     kGOOGLE_API_KEY];
url = [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

NSLog(@"%@", url);

//Formulate the string as a URL object.
NSURL *googleRequestURL=[NSURL URLWithString:url];

// Retrieve the results of the URL.
dispatch_async(kBgQueue, ^{
    NSData* data = [NSData dataWithContentsOfURL: googleRequestURL];
    [self performSelectorOnMainThread:@selector(fetchedData:) withObject:data  waitUntilDone:YES];
});
}

-(void)fetchedData:(NSData *)responseData {
//parse out the json data
NSError* error;
NSDictionary* json = [NSJSONSerialization
                      JSONObjectWithData:responseData

                      options:kNilOptions
                      error:&error];

//The results from Google will be an array obtained from the NSDictionary object with the  key "results".
NSArray* places = [json objectForKey:@"results"];

//Write out the data to the console.
NSLog(@"Google Data: %@", places);
}

-(void)mapView:(MKMapView *)mapView regionDidChangeAnimated:(BOOL)animated {
//Get the east and west points on the map so you can calculate the distance (zoom level)  of the current map view.
MKMapRect mRect = self.mapView.visibleMapRect;
MKMapPoint eastMapPoint = MKMapPointMake(MKMapRectGetMinX(mRect),  MKMapRectGetMidY(mRect));
MKMapPoint westMapPoint = MKMapPointMake(MKMapRectGetMaxX(mRect), MKMapRectGetMidY(mRect));

//Set your current distance instance variable.
currenDist = MKMetersBetweenMapPoints(eastMapPoint, westMapPoint);

//Set your current center point on the map instance variable.
currentCentre = self.mapView.centerCoordinate;
}

#pragma mark - MKMapViewDelegate methods.
- (void)mapView:(MKMapView *)mv didAddAnnotationViews:(NSArray *)views {
MKCoordinateRegion region;
region =  MKCoordinateRegionMakeWithDistance(locationManager.location.coordinate,1000,1000);


[mv setRegion:region animated:YES];
}

@end

我的最终格式化 URL 的控制台日志是:

https://maps.googleapis.com/maps/api/place/search/json? location=HIDDENLAT,HIDDENLONG&radius=995&types=bar&sensor=true&key=HIDDENAPI

我已经替换了上面生成的 lat、long 和 API 值,但它们被返回为正确的值?

我发现的另一个 SO 答案说要添加:

url = [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

我做了,但这对我不起作用?

任何想法为什么这不起作用!?我把头发拉出来试图把它弄出来!

谢谢!

4

2 回答 2

2

对于未来的答案寻求者,这可能是许多问题,包括您的 API 密钥、搜索半径或搜索“类型”或 JSON 解析问题。但是,代码应该与 Gary Stewart 在上面发布的完全一样。他甚至只是通过提出问题来帮助我找到答案......

NSLog(@"%@", url);像上面那样在 queryGooglePlaces 方法中的 URL 字符串之后添加。这会将 URL 请求记录到您的控制台,以便您可以确保它按预期编译。如果是,但您仍然没有取回数据,请复制您从控制台生成的 URL 并在 Web 浏览器中打开它。在生成页面的底部,它会告诉您为什么没有获取数据。

来自谷歌的开发者文档:

搜索响应对象中的“状态”字段包含请求的状态,并且可能包含调试信息以帮助您跟踪请求失败的原因。“状态”字段可能包含以下值:

OK表示没有发生错误;已成功检测到该地点并返回了至少一个结果。ZERO_RESULTS表示搜索成功但未返回任何结果。如果在远程位置通过 latlng 进行搜索,则可能会发生这种情况。 OVER_QUERY_LIMIT表示您已超出配额。 REQUEST_DENIED表示您的请求被拒绝,通常是因为缺少传感器参数。INVALID_REQUEST通常表示缺少必需的查询参数(位置或半径)。

我的问题是我发送的是“早餐”的搜索“类型”,而不是简单的“食物”。愚蠢的我,“早餐”将是一个关键字,而不是一个类型。

(顺便说一下,这里是支持的类型列表:https ://developers.google.com/places/documentation/supported_types )

希望这有助于发现您的问题。祝你好运!

于 2014-01-13T04:11:28.720 回答
1

改变

@"https://maps.googleapis.com/maps/api/place/search/json?  location=%f,%f&radius=%@&types=%@&sensor=true&key=%@"

@"https://maps.googleapis.com/maps/api/place/search/json?location=%f,%f&radius=%@&types=%@&sensor=true&key=%@"

(即,url 模板字符串中的 ? 后面没有空格)

于 2013-10-22T23:55:18.783 回答