2

如果每个员工有多个联系人值，我会得到多行，但我只希望每个员工有一行列出他们的姓氏、名字、部门名称、电子邮件和电话。

所以它应该像这样

    First Name    Last Name    Division     Email                  Phone
       Test          Guy         Exec     test@gmail.com        555-5555

这是我所拥有的，但它不起作用：

    SELECT sr.LastName, sr.FirstName, dd.Name, 
        Email = (select sc.ContactValue FROM StaffContactInformation as sc
         INNER JOIN StaffRoster as roster on sc.StaffID = roster.ID
         where sc.ContactTypeID = 3 and roster.ID = sr.ID),
Phone = (SELECT sc1.ContactValue FROM StaffContactInformation as sc1 
        INNER JOIN StaffRoster as roster on sc1.StaffID = roster.ID
        where sc1.ContactTypeID = 1) 
    FROM StaffRoster as sr
    left join dictDivisions as dd on sr.DivisionID = dd.Id  
    left join StaffContactInformation as sci on sr.ID = sci.StaffID
    inner join dictStaffContactTypes as dsct on sci.ContactTypeID = dsct.ID 
    where (sr.Active = 1 and sr.isContractor = 0 )
    ORDER BY sr.LastName, sr.FirstName

我通过以下查询解决了它：

    SELECT sr.LastName, sr.FirstName, dd.Name, 
        Email = (select sc.ContactValue FROM StaffContactInformation as sc
         INNER JOIN StaffRoster as roster on sc.StaffID = roster.ID
         where sc.ContactTypeID = 3 and roster.ID = sr.ID),
Phone = (SELECT sc.ContactValue FROM StaffContactInformation as sc 
        INNER JOIN StaffRoster as roster on sc.StaffID = roster.ID
        where sc.ContactTypeID = 1 and roster.ID = sr.ID) 
    FROM StaffRoster as sr
    left join dictDivisions as dd on sr.DivisionID = dd.Id 
    where (sr.Active = 1 and sr.isContractor = 0 )
    ORDER BY sr.LastName, sr.FirstName
4

2 回答 2

1

如果您选择email并phone在子查询中，这两个连接可能是不必要的：

left join StaffContactInformation as sci on sr.ID = sci.StaffID
inner join dictStaffContactTypes as dsct on sci.ContactTypeID = dsct.ID

由于它们，您获得的行数与特定人的联系人一样多。

最终查询可能如下所示：

SELECT sr.LastName, sr.FirstName, dd.Name, 
    Email = (
        select sc.ContactValue FROM StaffContactInformation as sc
        INNER JOIN StaffRoster as roster on sc.StaffID = roster.ID
        where sc.ContactTypeID = 3 and roster.ID = sr.ID
    ),
    Phone = (
        SELECT sc1.ContactValue FROM StaffContactInformation as sc1 
        INNER JOIN StaffRoster as roster on sc1.StaffID = roster.ID
        where sc1.ContactTypeID = 1
    ) 
FROM StaffRoster as sr
left join dictDivisions as dd on sr.DivisionID = dd.Id  
where (sr.Active = 1 and sr.isContractor = 0 )
ORDER BY sr.LastName, sr.FirstName
于 2013-10-21T16:27:46.043 回答
0

如果您运行的是 SQL Server 2005+，则可以使用数据透视表。在这里，我声明了一个 CTE 来封装数据透视表，您可以使用它加入查询的其余部分：

;with ContactInfo( StaffId, Email, Phone )
as
(
    select
        sci.StaffID
        , [3] Email
        , [1] Phone
    from
        StaffContractInformation sci
        PIVOT( MAX(ContactValue) for ContactTypeId in ( [3], [1] ) PivotTable

)

SELECT 
    sr.LastName, 
    sr.FirstName, 
    dd.Name, 
    ci.Email,
    ci.Phone
FROM 
    StaffRoster as sr
    left join dictDivisions as dd 
     on sr.DivisionID = dd.Id  
    left join ContactInfo ci
     on sr.ID = ci.StaffID
  --  inner join dictStaffContactTypes as dsct 
     --on sci.ContactTypeID = dsct.ID 
where 
    sr.Active = 1 
    and sr.isContractor = 0
ORDER BY 
    sr.LastName, 
    sr.FirstName
于 2013-10-21T16:37:26.457 回答