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我有这个 XML 响应：http: //jsfiddle.net/ZeeHv/

我正在尝试使用转储中的信息创建类似的东西：

<UL>
  <li>Academic
    <ul>
      <li>BM</li>
      <li>CMTTE</LI>
      <li>DM</li>
      <li>PM</li>
  </ul>
  </li>
</ul>
<ul>
  <li>ARCHIVE</li>
</UL>
<ul>
  <LI>ASSOCIATIONS
    <ul>
    <li>BM</li>
    <li>DM</LI>
    <li>PM</li>
    </ul>
  </LI>
</ul>

最后，XML 可以为我提供我所有站点和子站点的列表：

https://hosted.demo.ca 
https://hosted.demo.ca/academic
https://hosted.demo.ca/academic/bm 
https://hosted.demo.ca/academic/cmtte 
https://hosted.demo.ca/academic/dm 
https://hosted.demo.ca/academic/pm 
https://hosted.demo.ca/archive 
https://hosted.demo.ca/associations 
https://hosted.demo.ca/associations/bm 
https://hosted.demo.ca/associations/dm 
https://hosted.demo.ca/associations/pm

如何浏览这些信息并附加 ul 和 li 标签来创建站点导航菜单？

JS用来获取XML：

function getAllSites(){
  $().SPServices({
    operation: "GetAllSubWebCollection",
    async: true,
      completefunc: function(xData, Status){
      $(xData.responseXML).find("Web").each(function(){
      console.log($(this).attr("Url"));
      });
    }
  });
}
4

1 回答 1

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一个简单的解决方案是根据链接的深度构建索引图，深度/由url.

var map = {}; //init the map
for (var i = 0, l = webs.length; i < l; i++) {
  //we create a index for our links based on the depth of them by `/`
  var m = webs[i].attributes['Url'].value.substring(23, webs[i].attributes['Url'].value.length).split('/').length; 

  map[m] = map[m] || []; //make sure we leave alone the old values if there is none init with new array
  map[m].push(webs[i].attributes['Url'].value); //push new value to node
}
console.log(map);

console.log(map);将输出一个类似这样的对象：

{
    "1": ["https://hosted.demo.ca", "https://hosted.demo.ca/academic", "https://hosted.demo.ca/archive", ...],
    "2": ["https://hosted.demo.ca/academic/bm", "https://hosted.demo.ca/academic/cmtte", ...],
}

从这里你可以创建你的元素列表。

于 2013-10-18T19:51:41.160 回答