在matlab中我使用
a=[1,4,6]
b=[1,2,3]
corr(a,b)
返回 .9934。我试过numpy.correlate
了,但它返回的东西完全不同。获得两个向量相关性的最简单方法是什么?
文档表明这numpy.correlate
不是您要查找的内容:
numpy.correlate(a, v, mode='valid', old_behavior=False)[source]
Cross-correlation of two 1-dimensional sequences.
This function computes the correlation as generally defined in signal processing texts:
z[k] = sum_n a[n] * conj(v[n+k])
with a and v sequences being zero-padded where necessary and conj being the conjugate.
相反,正如其他评论所建议的那样,您正在寻找Pearson 相关系数。要使用 scipy 尝试执行此操作:
from scipy.stats.stats import pearsonr
a = [1,4,6]
b = [1,2,3]
print(pearsonr(a,b))
这给
(0.99339926779878274, 0.073186395040328034)
您还可以使用numpy.corrcoef
:
import numpy
print(numpy.corrcoef(a,b))
这给出了:
[[ 1. 0.99339927]
[ 0.99339927 1. ]]