我的代码有问题...如果实现了 javascript,函数 retmsg 没有返回值
<div id="pop">
<a href="#" class="title">Elunika</a>
<div class="txt">Its the way to connect with your friends.</div>
<form action="login.php" method="post" id="login">
<input id="email" placeholder="E-mail" type="text" name="em" />
<input id="email" placeholder="Password" type="password" name="pwd"/>
<div class="txt1"><input type="checkbox" name="check" />Keep me logged in |<a href="#"> Forgot Password ?</a></div>
<input id="loginButton" type="submit" value="Login" name="log" />
</form>
<a href="#" id="reg"><span>Register</span></a>
<div id="error1"></div>
<div id="termdiv1"></div>
</div>
从 retmsg() 函数返回的值应显示在 div id="error" 中
登录脚本...
if (isset($c))
{
$q = mysql_query("select * from registeration where email='$a' and password='$b'");
$r = mysql_num_rows($q);
if($r)
{
$_SESSION["Authenticated"] = 1;
$_SESSION['id'] = $a;
echo retmsg(1,"profile.php");
}
else
{
$_SESSION["Authenticated"] = 0;
die (retmsg(0,"Incorrect Information"));
}
}
function retmsg($status,$txt)
{
return '{"status":'.$status.',"txt":"'.$txt.'"}';
}
javascript代码...
$(document).ready(function(){
$('#login').submit(function(e) {
att();
e.preventDefault();
});
$('#regForm').submit(function(e) {
register();
e.preventDefault();
});
});
function register()
{
hideshow('loading',1);
error(0);
$.ajax({
type: "POST",
url: "submit.php",
data: $('#regForm').serialize(),
dataType: "json",
success: function(msg){
if(parseInt(msg.status)==1)
{
window.location=msg.txt;
}
else if(parseInt(msg.status)==0)
{
error(1,msg.txt);
}
hideshow('loading',0);
}
});
}
function hideshow(el,act)
{
if(act) $('#'+el).css('visibility','visible');
else $('#'+el).css('visibility','hidden');
}
function error(act,txt)
{
hideshow('error',act);
if(txt) {
$('#error').html(txt);
$('#regpop').css('height','419px');
$('#termdiv').css('margin-top','10px');
}
if(!txt) {
$('#regpop').css('height','400px');
$('#termdiv').css('margin-top','-20px');
}
}
function att()
{
hideshow1('loading',1);
error1(0);
$.ajax({
type: "POST",
url: "login.php",
data: $('#login').serialize(),
dataType: "json",
success: function(retmsg){
if(parseInt(retmsg.status)==1)
{
window.location=retmsg.txt;
}
else if(parseInt(retmsg.status)==0)
{
error1(1,retmsg.txt);
}
hideshow1('loading',0);
}
});
}
function hideshow1(el,act)
{
if(act) $('#'+el).css('visibility','visible');
else $('#'+el).css('visibility','hidden');
}
function error1(act,txt)
{
hideshow1('error1',act);
if(txt) {
$('#error1').html(txt);
$('#pop').css('height','290px');
$('#termdiv1').css('margin-top','50px');
}
if(!txt) {
$('#pop').css('height','270px');
$('#termdiv1').css('margin-top','-35px');
}
}
在 javascript 代码中,retmsg 应该将 txt 参数返回给 att 函数..... att 函数正在将 retmsg.txt 值传递给 error1 函数,函数 error1 的一部分正在工作,因为 retmsg.txt 没有返回值...
其余的 javascript 代码工作正常……其余代码与此相同……只是函数名称不同……
回答*回答*回答
javascript 代码都是正确的 在登录脚本中进行了更改
$q = mysql_query("select * from registeration where email='$a' and password='$b'");
$r = mysql_num_rows($q);
if(!$r)
{
$_SESSION["Authenticated"] = 0;
die (retmsg(0,"Incorrect Information"));
}
else
{
$_SESSION["Authenticated"] = 1;
$_SESSION['id'] = $a;
echo retmsg(1,"profile.php");
}
function retmsg($status,$txt)
{
return json_encode(array('status' => $status, 'txt' => $txt));
}