java - 如何将日期差作为具有毫秒精度的浮点数

Question

public static void main(String[] args) throws InterruptedException{
    long sTime =  new Date().getTime();
    Thread.sleep(3234);
    long eTime =  new Date().getTime();
    float diff = ((eTime-sTime)/1000);
    System.out.println(diff);
}

在上面的代码中，我期望输出为 3.234 但它是 3.0。我想要以秒为单位的两次之间的确切差异，并带有小数部分。

Answer 1

您正在执行整数除法而不是浮点除法。尝试这个：

float diff = ((float)(eTime-sTime)/1000.0);

当您使用longs 时，我进一步建议您使用double数据类型以获得更高的精度：

double diff = ((double)(eTime-sTime)/1000.0);

Answer 2

    double sTime =  new Date().getTime();
    Thread.sleep(3234);
    double eTime =  new Date().getTime();
    double diff = ((eTime-sTime)/1000);
    System.out.println(diff);