0

我有一个查询,它切断每一行的域后缀,例如 google.com -> google 或 google.co.uk -> google

查询如下

SELECT id,domain, 
CASE 
WHEN LENGTH(domain) - LENGTH(REPLACE(domain, '.', '')) = 1 THEN REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000))
WHEN LENGTH(domain) - LENGTH(REPLACE(domain, '.', '')) = 2 THEN REVERSE(SUBSTRING(REVERSE(REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000))), LOCATE('.', REVERSE(REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000)))) + 1, 1000))

END as Keydomain
FROM sites

现在我想显示不止一次出现的所有修改域。我怎样才能做到这一点?谢谢你的协助 ;)

4

1 回答 1

0

只需添加

GROUP BY Keydomain
HAVING COUNT(*) > 1

到您的查询。

编辑:

您能否告诉我是否有一种方法可以通过您的添加一个一个地列出完整的域?

SELECT * FROM
(
SELECT 
CASE 
WHEN LENGTH(domain) - LENGTH(REPLACE(domain, '.', '')) = 1 THEN REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000))
WHEN LENGTH(domain) - LENGTH(REPLACE(domain, '.', '')) = 2 THEN REVERSE(SUBSTRING(REVERSE(REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000))), LOCATE('.', REVERSE(REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000)))) + 1, 1000))
END as Keydomain
FROM sites
GROUP BY Keydomain
HAVING COUNT(*) > 1
) d1
INNER JOIN
(
SELECT id, domain,
CASE 
WHEN LENGTH(domain) - LENGTH(REPLACE(domain, '.', '')) = 1 THEN REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000))
WHEN LENGTH(domain) - LENGTH(REPLACE(domain, '.', '')) = 2 THEN REVERSE(SUBSTRING(REVERSE(REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000))), LOCATE('.', REVERSE(REVERSE(SUBSTRING(REVERSE(domain), LOCATE('.', REVERSE(domain)) + 1, 1000)))) + 1, 1000))
END as Keydomain
FROM sites
) d2
ON d1.Keydomain = d2.Keydomain
于 2013-10-14T09:28:19.093 回答