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I have edited the SQL to use DISTINCT however I am still getting the same data as when I use GROUP BY. Any suggestions? When I use GROUP BY it requires that all the fields in the select clause are included, can anyone tell me why that is?

Any help is greatly appreciated.

SELECT DISTINCT 
TrnClaim.ClientID
, TrnClaim.FileNo
, TrnLegend.RecordNo
, RTRIM(dbo.TrnClient.ClientName + ' ' + ISNULL(dbo.TrnClient.Initials,'') + ' ' +     (CASE WHEN dbo.TrnClient.LanguageCode = 'A' THEN ISNULL(dbo.TrnClient.Title, 'Mr') ELSE ISNULL(dbo.TrnClient.Title,'')END)) AS NameInitials
, TrnClient.IDNumber
, ISNULL(dbo.MstInsurer.InsurerName, 'Unknown') AS InsurerName
, CAST(dbo.TrnPolicy.AgentID AS VARCHAR(10)) + ' ' + ISNULL(CAST(dbo.MstAgent.AgentName AS VARCHAR(50)),'Unknown') AS AgentIDName
, CAST(dbo.TrnPolicy.TeamID AS VARCHAR(10)) + ' ' + ISNULL(dbo.VieTeamSelect.TeamName, 'Unknown') AS TeamIDName
, CAST(dbo.TrnPolicy.LinkID AS VARCHAR(10)) + ' ' + ISNULL(dbo.MstLink.LinkName, 'Unknown') AS LinkIDName
, CAST(dbo.TrnPolicy.SubagentID AS VARCHAR(10)) + ' ' + ISNULL(dbo.MstSubagent.SubagentName, 'Unknown') AS SubagentIDName
, CAST(dbo.TrnPolicy.MarketerID AS VARCHAR(10)) + ' ' + ISNULL(dbo.MstMarketerCodes.MarketerName, 'Unknown') AS MarketerIDName
, dbo.TrnRisk.RiskID
, dbo.TrnRisk.Registration
, dbo.TrnRisk.VehID
, dbo.TrnRisk.VinNo
, dbo.TrnRisk.VehMake
, dbo.TrnRisk.VehMake
, dbo.TrnRisk.VehModel
, dbo.TrnRisk.VehModel
, dbo.TrnExt.ExtStartDate
, dbo.TrnExt.ExtEndDate
, dbo.MstRateCodes.RateCodeID
, dbo.TrnExt.ExtDesc
, dbo.TrnPolicy.Status AS PolicyStatus
, dbo.TrnPolicy.PayMeth
, dbo.TrnPolicy.PolicyPeriod
, 1 AS [Count]
, dbo.TrnPolicy.TotalPrem AS LastMonthPremium
--, LastPolicy.TotalDue AS LastMonthTotalDue
, dbo.TrnPolicy.TeamID
, dbo.TrnPolicy.AgentID
, dbo.TrnPolicy.LinkID
, ISNULL(dbo.TrnPolicy.LeadInsurerID,MstInsurer.InsurerID) AS InsurerIDForFilter
, dbo.TrnLegend.LegendDescr
, dbo.TrnLegend.ActiveDate

FROM dbo.TrnClaim

INNER JOIN dbo.TrnPolicy ON
    TrnClaim.ClientID = dbo.TrnPolicy.ClientID 
    AND
    TrnClaim.FileNo = dbo.TrnPolicy.FileNo 

INNER JOIN dbo.TrnClient ON 
    dbo.TrnPolicy.ClientID = dbo.TrnClient.ClientID 

INNER JOIN dbo.TrnRisk ON 
    dbo.TrnPolicy.ClientID = dbo.TrnRisk.ClientID 
    AND 
    dbo.TrnPolicy.FileNo = dbo.TrnRisk.FileNo 

INNER JOIN dbo.TrnExt ON 
    dbo.TrnRisk.ClientID = dbo.TrnExt.ClientID 
    AND 
    dbo.TrnRisk.FileNo = dbo.TrnExt.FileNo 

LEFT OUTER JOIN dbo.MstRateCodes ON 
    dbo.MstRateCodes.RateCodeID = dbo.TrnExt.ExtCode    

LEFT OUTER JOIN dbo.MstInsurer MstInsurerLead ON 
    dbo.TrnPolicy.LeadInsurerID = MstInsurerLead.InsurerID 

LEFT OUTER JOIN dbo.TrnPolicy LastPolicy ON  
    dbo.TrnPolicy.ClientID = LastPolicy.ClientID 
    AND 
    dbo.TrnPolicy.FileNo = LastPolicy.FileNo 

LEFT OUTER JOIN dbo.MstAgent ON 
    dbo.TrnPolicy.AgentID = dbo.MstAgent.AgentID 

LEFT OUTER JOIN dbo.MstSubagent ON 
    dbo.TrnPolicy.SubagentID = dbo.MstSubagent.SubagentID 

LEFT OUTER JOIN dbo.MstMarketerCodes ON 
    dbo.TrnPolicy.MarketerID = dbo.MstMarketerCodes.MarketerID 

LEFT OUTER JOIN dbo.VieTeamSelect ON
    dbo.TrnPolicy.TeamID = dbo.VieTeamSelect.TeamID 

LEFT OUTER JOIN dbo.MstLink ON  
    dbo.TrnPolicy.LinkID = dbo.MstLink.LinkID 

LEFT OUTER JOIN dbo.MstInsurer ON 
    dbo.MstInsurer.InsurerID= dbo.TrnClaim.InsurerID

INNER JOIN dbo.TrnLegend On
    dbo.TrnLegend.ClientID = dbo.TrnClaim.ClientID
    AND
    dbo.TrnLegend.FileNo = dbo.TrnClaim.FileNo


WHERE 
Upper(dbo.TrnLegend.LegendDescr) LIKE '%CANCELLED%'

Order By 
dbo.TrnClaim.ClientID
, dbo.TrnClaim.FileNo
, dbo.TrnLegendRecordNo
4

1 回答 1

0

使用Group By时指定属性列表。包含GROUP BY子句的查询根据属于分组集的属性值的每个唯一组合为每个组生成一行

因此,当GROUP BY在查询中指定时,所有后续步骤(HAVING、SELECT 等)只能指定每个组具有标量(单数)值的表达式。这些表达式可以包括 GROUP BY 列表中的列或表达式,例如 TrnClaim.ClientID — 或聚合函数,例如 COUNT(TrnClaim.ClientID)。

正如我所看到的,您在上面的查询中没有包含任何聚合函数,这就是为什么当您编写说 Group By (TrnClaim.ClientID) 或任何其他列时,没有创建任何组或重新表述每一行成为一个唯一组,因此它需要选择子句中的所有字段都包括在内。

这就是您使用 Distinct 和 GROUP BY 获得相同数据的原因,因为没有创建任何组。

于 2013-10-14T11:30:01.040 回答