python - 从 requests.exceptions.HTTPError 获取 HTTP 错误代码

Question

我正在捕捉这样的异常，

def get_url_fp(image_url, request_kwargs=None):
    response = requests.get(some_url, **request_kwargs)
    response.raise_for_status()
    return response.raw


try:
   a = "http://example.com"
   fp = get_url_fp(a)

except HTTPError as e:
    # Need to check its an 404, 503, 500, 403 etc.

Answer 1

HTTPError随身携带Response物体：

def get_url_fp(image_url, request_kwargs=None):
    response = requests.get(some_url, **request_kwargs)
    response.raise_for_status()
    return response.raw


try:
    a = "http://example.com"
    fp = get_url_fp(a)

except HTTPError as e:
    # Need to check its an 404, 503, 500, 403 etc.
    status_code = e.response.status_code

Answer 2

这是我在 HTTP 中获取错误代码的代码

def tomcat_status(ip,port,url):
    try:
    # you can give your own url is
       r = urllib2.urlopen('http://'+ip+':'+port+'/'+url)
       return r.getcode()
     except urllib2.HTTPError as e:
       return e.code
    except urllib2.URLError as f:
       return 1
print tomcat_status(ip,tomcat_port,ping_url)