我正在实现一个惰性登录功能。我的黄瓜功能应该描述它:
Feature: User log in
Scenario: Lazy login
Given I didn't log out the last time I was on the site
When I go to the homepage
Then I should automatically be logged in
这些是我的步骤定义:
Given(/^I didn't log out the last time I was on the site$/) do
user = FactoryGirl.create(:user)
visit new_user_session_path
fill_in('user[email]', with: user.email)
fill_in('user[password]', with: 'test123')
click_button('Sign in')
Capybara.reset_sessions!
end
When(/^I go to the homepage$/) do
visit root_path
end
Then(/^I should automatically be logged in$/) do #<-- Fails here
page.should have_content("Logout")
end
这就是用户登录时发生的情况:cookies.signed[:auth_token]
gets 设置。这将由我的 ApplicationController 中的前置过滤器使用,以便打开新浏览器的用户将自动登录:
class SessionsController < Devise::SessionsController
def create
super
if user_signed_in?
puts 'yesssssss'
session[:user_id] = current_user.id
current_user.remember_me! if current_user.remember_token.blank?
cookies.signed[:auth_token] = {
:value => current_user.remember_token,
:domain => "mysite.com",
:secure => !(Rails.env.test? || Rails.env.development?)
}
puts "current_user.remember_token = #{current_user.remember_token}"
puts 'cookies:'
puts cookies.signed[:auth_token]
end
end
结尾
这是我的 ApplicationController 中的前置过滤器:
def sign_in_through_cookie
logger.info "logging in by cookie"
puts "logging in by cookie"
puts cookies.signed[:auth_token] #<-- PROBLEM: this returns nil.
return true if !current_user.nil?
if !cookies[:auth_token].nil? && cookies[:auth_token] != ''
user = User.find_by_remember_token(cookies.signed[:auth_token])
return false if user.blank?
sign_in(user)
puts 'success'
return true
else
return false
end
end
所以问题是在我的黄瓜功能的最后一步,cookies.signed[:auth_token]
返回零。我猜这只是水豚的事情。那么我实际上是否必须在测试中设置一个 cookie 而不是在我的控制器中使用一个?