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This is findind limit calculus one. This would be very easy but i never factor high degrees. can anyone show me how to factor it.

lim((x^5-32)/(x-2),x=2)

lim((x^5-2^5)/(x-2),x=2)

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1 回答 1

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正如约翰在上面的评论中所建议的那样:当 x-->2 我们处理 0/0 类型的限制时。为了计算它,我们使用分子的导数和分母的导数:

f'(X^5-2^5) = 5x^4
----------    ----
f'(x-2)     = 1

如果我们将 x 替换为 2,我们将得到:

5*2^4
----- = 80
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于 2013-10-11T03:25:35.757 回答