2

我有从 URL 获得的下一个 JSON：

[{
  "id": 1,
  "version": 23,
  "external_id": "2312",
  "url": "https://example.com/432",
  "type": "typeA",
  "date": "2",
  "notes": "notes",
  "title": "title",
  "abstract": "dsadasdas",
  "details": "something",
  "accuracy": 0,
  "reliability": 0,
  "severity": 12,
  "thing": "32132",
  "other": [
    "aaaaaaaaaaaaaaaaaa",
    "bbbbbbbbbbbbbb",
    "cccccccccccccccc",
    "dddddddddddddd",
    "eeeeeeeeee"
  ],
  "nana": 8
},
{
  "id": 2,
  "version": 23,
  "external_id": "2312",
  "url": "https://example.com/432",
  "type": "typeA",
  "date": "2",
  "notes": "notes",
  "title": "title",
  "abstract": "dsadasdas",
  "details": "something",
  "accuracy": 0,
  "reliability": 0,
  "severity": 12,
  "thing": "32132",
  "other": [
    "aaaaaaaaaaaaaaaaaa",
    "bbbbbbbbbbbbbb",
    "cccccccccccccccc",
    "dddddddddddddd",
    "eeeeeeeeee"
  ],
  "nana": 8
}]

我的代码：

import json
import urllib2

data = json.load(urllib2.urlopen('http://someurl/path/to/json'))
print data

例如，我想知道如何访问“id”等于 2 的对象的“抽象”部分。“id”部分是唯一的，所以我可以使用 id 来索引我的搜索。

谢谢！

4

3 回答 3

3

这是一种方法。您可以通过生成器表达式创建生成器，调用next以迭代该生成器一次，然后取回所需的对象。

item = next((item for item in data if item['id'] == 2), None)
if item:
    print item['abstract']

另请参见Python：根据字典中的内容从列表中获取字典

编辑：如果您想访问列表中具有给定键值的所有id == 2元素（例如， ），您可以执行以下两项操作之一。您可以通过理解创建一个列表（如另一个答案所示），也可以更改我的解决方案：

my_gen = (item for item in data if item['id'] == 2)
for item in my_gen:
    print item

在循环中，item将遍历列表中满足给定条件的那些项目（此处为id == 2）。

于 2013-10-10T19:47:24.870 回答
2

您可以使用列表理解来过滤：

import json

j = """[{"id":1,"version":23,"external_id":"2312","url":"https://example.com/432","type":"typeA","date":"2","notes":"notes","title":"title","abstract":"dsadasdas","details":"something","accuracy":0,"reliability":0,"severity":12,"thing":"32132","other":["aaaaaaaaaaaaaaaaaa","bbbbbbbbbbbbbb","cccccccccccccccc","dddddddddddddd","eeeeeeeeee"],"nana":8},{"id":2,"version":23,"external_id":"2312","url":"https://example.com/432","type":"typeA","date":"2","notes":"notes","title":"title","abstract":"dsadasdas","details":"something","accuracy":0,"reliability":0,"severity":12,"thing":"32132","other":["aaaaaaaaaaaaaaaaaa","bbbbbbbbbbbbbb","cccccccccccccccc","dddddddddddddd","eeeeeeeeee"],"nana":8}]"""

dicto = json.loads(j)

results = [x for x in dicto if "id" in x and x["id"]==2]

然后你可以像这样打印“抽象”值：

for result in results:
    if "abstract" in result:
        print result["abstract"]
于 2013-10-10T19:54:21.673 回答
0 
import urllib2
import json
data = json.load(urllib2.urlopen('http://someurl/path/to/json'))
your_id = raw_input('enter the id')
for each in data:
    if each['id'] == your_id:
        print each['abstract']

在上面的代码中，数据是列表，每个都是一个字典，您可以轻松访问该字典对象。

于 2013-10-15T14:36:44.063 回答