-3

当我对字符串进行编码时。它给出了这样的错误UnicodeDecodeError: 'ascii' codec can't decode byte 0xe9 in position 304: ordinal not in range(128)

value = ""
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"""



In [2]: type(value)
Out[2]: str

In [3]: encoded_value = value.encode("utf-8")
---------------------------------------------------------------------------
UnicodeDecodeError                        Traceback (most recent call last)
/home/nyros/hs/1a9pinaxenv/local/lib/python2.7/site-packages/django/core/management/commands/shell.pyc in <module>()
----> 1 encoded_value = value.encode("utf-8")

UnicodeDecodeError: 'ascii' codec can't decode byte 0xe9 in position 304: ordinal not in range(128)

In [4]:
4

1 回答 1

1

这是我用你的value

>>> type(value)
<type 'str'>

>>> v = value.decode('utf-8')
>>> type(v)
<type 'unicode'>

如果您想知道您value是编码还是解码，您可以从错误消息中看到，UnicodeDecodeError如果您尝试encode使用已编码的字符串，则会引发 a。

那么如何尝试然后捕获异常：

try:
    value = value.encode('utf-8')
except UnicodeDecodeError:
    print('It is already a UTF-8 encoded string')
else:
    print('It may have been a UTF-8 encoded string')
于 2013-10-09T06:29:18.417 回答