我目前正在为 iOS 创建一个非常基本的游戏。基本上,我在屏幕上设置了动画方块,以及使用加速度计控制的“船”。我想检测船何时撞到正在移动的方块,并且由于某种原因我的代码无法正常工作。
在这个块中,我正在创建一个正方形的动画:
square4 = [[UIImageView alloc] initWithFrame: CGRectMake(frameWidth/10, frameHeight/1.35, frameWidth*.1, frameWidth*.1)];
square4.image = [UIImage imageNamed: @"square.png"];
[self.view addSubview: square4];
CGPoint origin4 = square4.center;
CGPoint target4 = CGPointMake(square4.center.x+300, square3.center.y);
CABasicAnimation *bounce4 = [CABasicAnimation animationWithKeyPath:@"position.x"];
bounce4.fromValue = [NSNumber numberWithInt:origin4.x];
bounce4.toValue = [NSNumber numberWithInt:target4.x];
bounce4.duration = 2.3;
bounce4.repeatCount = HUGE_VALF;
bounce4.autoreverses = YES;
[square4.layer addAnimation:bounce4 forKey:@"position"];
然后我创建了我的船,并设置了加速度计等。我遇到的问题是,当我运行这个方法时,船和广场发生碰撞,什么也没有发生!这是我的碰撞方法代码:
- (void)collisionWithSquares {
CALayer *squareLayer1 = [square.layer presentationLayer];
CALayer *squareLayer2 = [square2.layer presentationLayer];
CALayer *squareLayer3 = [square3.layer presentationLayer];
CALayer *squareLayer4 = [square4.layer presentationLayer];
if (CGRectIntersectsRect(ship.frame, squareLayer1.frame)
|| CGRectIntersectsRect(ship.frame, squareLayer2.frame)
|| CGRectIntersectsRect(ship.frame, squareLayer3.frame)
|| CGRectIntersectsRect(ship.frame, squareLayer4.frame) ) {
//self.currentPoint = CGPointMake(0, 144);
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Oops!"
message:@"Mission Failed!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
}
}
我在我的 init 方法中在这里调用 [self collisionWithSquares]:
self.motionManager = [[CMMotionManager alloc] init];
self.motionManager.accelerometerUpdateInterval = .05;
//accelerometer queues up the data
//handler calls outputaccelera
[self.motionManager startAccelerometerUpdatesToQueue:[NSOperationQueue currentQueue] withHandler:^(CMAccelerometerData *accelerometerData, NSError *error)
{
[self outputAccelerationData:accelerometerData.acceleration];
}];
[self.view addSubview: ship];
[self collisionWithSquares];
}
return self;
}