6

我正在开发 TCP 服务器/客户端应用程序。

我的问题是：

我的服务器应用程序启动一个新线程并阻止它，直到连接被接受 listenforClient 方法

但是，当多个客户端连接到我的服务器并且它们同时请求不同的东西时，我该如何管理连接，我如何管理客户端 1 获取其需要的信息，以及客户端 2 的相同信息。

它是多线程的，因此可以连接多个客户端，但我如何处理请求。我不想把所有东西都放在一种方法中。

提前致谢

private void serverstart()
    {
        this.tcplistener = new TcpListener(IPAddress.Any, 49151);
        this.listenThread = new Thread(new ThreadStart(ListenForClients));
        this.listenThread.Start();
    }

    private void ListenForClients()
    {
        this.tcplistener.Start();

        while (true)
        {
            //blocks until a client has connected to the server
            TcpClient client = this.tcplistener.AcceptTcpClient();


            // here was first an message that send hello client
            //
            ///////////////////////////////////////////////////

            //create a thread to handle communication
            //with connected client
            Thread clientThread = new Thread(new ParameterizedThreadStart(HandleClientComm));

            clientThread.Start(client);
        }
    }

    private void HandleClientComm(object client)
    {
        TcpClient tcpClient = (TcpClient)client;
        NetworkStream clientStream = tcpClient.GetStream();

        byte[] message = new byte[4096];
        int bytesRead;

        while (true)
        {
            bytesRead = 0;

            try
            {
                //blocks until a client sends a message
                bytesRead = clientStream.Read(message, 0, 4096);
            }
            catch
            {
                //a socket error has occured
                break;
            }

            if (bytesRead == 0)
            {
                //the client has disconnected from the server
                break;
            }

            //message has successfully been received
            ASCIIEncoding encoder = new ASCIIEncoding();

            bufferincmessage = encoder.GetString(message, 0, bytesRead);


            if (System.Text.RegularExpressions.Regex.IsMatch(bufferincmessage, Properties.Settings.Default.REQLogin, System.Text.RegularExpressions.RegexOptions.IgnoreCase))
            {
                bufferincmessageresult = bufferincmessage.Split('^');
                nickname_Cl = bufferincmessageresult[1];
                password_Cl = bufferincmessageresult[2];
                getuserdata_db();
                login();

                byte[] buffer = encoder.GetBytes(inlogmessage);

                clientStream.Write(buffer, 0, buffer.Length);
                clientStream.Flush();
            }


        }
    }
4

1 回答 1

5

您的客户端将在不同的线程中分派，因此它们不会相交。您只需要添加诸如“DispatchMethod”之类的内容即可处理您的消息。

using System.Text.RegularExpressions;
...

if (Regex.IsMatch(bufferincmessage, Properties.Settings.Default.REQLogin, RegexOptions.IgnoreCase))
{
    ...
}
else if (Regex.IsMatch(bufferincmessage, /*some of your command1*/, RegexOptions.IgnoreCase))
{
    ...
}
else if (Regex.IsMatch(bufferincmessage, /*some of your command1*/, RegexOptions.IgnoreCase))
{
    ...
}
于 2013-10-07T07:07:29.393 回答