0

我有以下查询

select m.movementid, m.orderid, m.pickupdate, m.pickupnotes, 
b.bin_size, b.bin_type, 
l.address, l.suburb, l.postcode, l.state, 
if(rs.run_action = 'Pick', if (r.run_state = 'Active' or r.run_state='Ready', 1, 0), 0) as active_on_pick
from bb_movement m
inner join bb_bins b on b.bin_id = m.bin_id
inner join bb_location l on l.locationid = m.locationid
inner join bb_runsheet rs on rs.movement_id = m.movementid
inner join bb_run r on r.run_id = rs.run_id
where m.mvtstate = 'Active'
order by m.locationid, m.pickupdate

我想产生一个结果，其中 active_on_pick 列包含每个运动标识的 0 或 1。当给定的motionid添加到bb_run时，bb_runsheet表中存在一条记录（一个bb_run可以有许多bb_runsheet记录，其中主要包含一个movementid）

我遇到的问题是，当运动正在进行时（即：有一个与标准匹配的 bb_run 记录和 bb_runsheet 表中的一个条目）我在结果数据集中得到 2 行 - 例如：

mvt_id active_on_pick
21     0
21     1

我想要的只是 21 和 1。我尝试了子查询和其他变体（例如按移动 ID 分组），但似乎可以解决问题。我正在使用 mysql

4

2 回答 2

1

我认为如果您将一些逻辑移动到您的联接中（更改为 LEFT JOIN），您可以获得答案，将更多逻辑移动到另一个左联接中

select m.movementid, m.orderid, m.pickupdate, m.pickupnotes, 
b.bin_size, b.bin_type, 
l.address, l.suburb, l.postcode, l.state, 

IF(r.run_id IS NULL, 0, 1) as active_on_pick

from bb_movement m
inner join bb_bins b on b.bin_id = m.bin_id
inner join bb_location l on l.locationid = m.locationid

LEFT join bb_runsheet rs 
 ON rs.movement_id = m.movementid
    AND rs.run_action = 'Pick'

LEFT join bb_run r 
  ON r.run_id = rs.run_id
    AND (r.run_state = 'Active' or r.run_state='Ready')

where m.mvtstate = 'Active'
order by m.locationid, m.pickupdate
于 2013-10-05T12:14:27.180 回答
0

你可以使用 row_Number()

SELECT * FROM (    
select row_number() over (order by active_on_pick desc) rn,
m.movementid, m.orderid, m.pickupdate, m.pickupnotes, 
b.bin_size, b.bin_type, 
l.address, l.suburb, l.postcode, l.state, 
if(rs.run_action = 'Pick', if (r.run_state = 'Active' or r.run_state='Ready', 1, 0), 0) 
as active_on_pick
from bb_movement m
inner join bb_bins b on b.bin_id = m.bin_id
inner join bb_location l on l.locationid = m.locationid
inner join bb_runsheet rs on rs.movement_id = m.movementid
inner join bb_run r on r.run_id = rs.run_id
where m.mvtstate = 'Active'
order by m.locationid, m.pickupdate
) SampleTable
Where rn = 1
于 2013-10-05T10:42:05.313 回答