ios - UIButton 被点击两次

Question

我需要以编程方式单击一个按钮：[play sendActionsForControlEvents:UIControlEventTouchUpInside]; 但是当我这样做时，void 被调用了两次！我需要启动一个 AVPlayer（在 ViewDidLoad 中），但音乐也开始了两次。请帮忙 ：）。

播放代码：

- (IBAction)playStream:(id)sender  {
    NSLog(@"%@", @"PlayStream clicked: ", sender);
        if(clicked == 0) {
        clicked = 1;
        [[UIApplication sharedApplication] beginReceivingRemoteControlEvents];
        [self becomeFirstResponder];
        [play setImage:[UIImage imageNamed:@"pause"] forState:UIControlStateNormal];
        [playerr play];
    }
    else {
        [playerr stop];
        [play setImage:[UIImage imageNamed:@"Start"] forState:UIControlStateNormal];
        [audio setActive:NO error:nil];
        clicked = 0;
    }
} 

Answer 1

怎么样：

@implementation MyClassName{
     BOOL musicPlaying;
}

- (IBAction)playStream:(id)sender  {
    if(musicPlaying){
        [self pauseMusic];
    }else{
        [self playMusic];
    }
}

-(void)playMusic{
    musicPlaying= YES;
    [play setImage:[UIImage imageNamed:@"pause"] forState:UIControlStateNormal];
    [playerr play];
}

-(void)pauseMusic{
    musicPlaying= NO;
    [playerr stop];
    [play setImage:[UIImage imageNamed:@"Start"] forState:UIControlStateNormal];
    [audio setActive:NO error:nil];
}

现在无需以编程方式点击按钮，只需调用 playMusic 或 pauseMusic。