php - 使用 preg 匹配返回 true 或 false，而不是回显一个句子

Question

我正在使用以下内容来检查表单中的数据是否包含某些单词，但问题是，当它检查时，我一遍又一遍地得到“找到匹配”或“找不到匹配”一百万次. 我怎样才能为发布的整个句子分配一个真值或假值？然后我想添加类似....如果为 true 转储此帖子，如果为 false 则对其进行处理并将其放入数据库中。

    <?php
    $message = $_POST['message'];
    echo $message;

    $targets = array('viagra', 'prescription', 'drugs', 'zyban', 'zithromax', 'voltaren', 'cilias', 'FDA');

    foreach($targets as $t)
    {
        if (preg_match("/\b" . $t . "\b/i", $message)) {
            echo "A match was found.";
        } else {
            echo "A match was not found.";
        }
    }

    ?>

Answer 1

function containsSpam($message) {
    $targets = array('viagra', 'prescription', 'drugs', 'zyban', 'zithromax', 'voltaren', 'cilias', 'FDA');

    foreach($targets as $t)
    {
        if (preg_match("/\b" . $t . "\b/i", $message)) {
            //A match was found.
            return true;
        }
    }
    return false;
}

Answer 2

如果我做对了，你需要像这样设置一个停止值

<?php
function containsSpam($message) {
    $targets = array('viagra', 'prescription', 'drugs', 'zyban', 'zithromax', 'voltaren', 'cilias', 'FDA');        
    $stop = false;
    foreach($targets as $t)
    {
        if (preg_match("/\b" . $t . "\b/i", $message)) {
            //A match was found.
            $stop = true;
            break;
        }
    }
    //And you can then do something like this
    if ($check) {
       //Insert it
    } else {
       //Dump it
    }
}
?>