python - 在标准 python 线程中发出信号

Question

我有一个线程应用程序，其中有一个网络线程。UI 部分将 a 传递callback给该线程。该线程是一个普通的python 线程 - 它是NO QThread。

是否可以在此线程中发出 PyQT Slot？

Answer 1

不，不可能像这样从 python 线程发出 PyQt 信号。

但是，一种可能的解决方案是使用两个线程共享的附加对象，进行必要的操作以最终发出线程安全的 PyQt 信号。

这是一个“SafeConnector”类的实现，利用一对连接的套接字和一个队列在两个线程之间交换数据，并使用一个 QSocketNotifier 回到 Qt 的循环中。QObject 用于使发出正确的 Qt 信号成为可能：

from PyQt4 import Qt, QtCore, QtGui
import threading
import socket
import Queue
import time

# Object of this class has to be shared between
# the two threads (Python and Qt one).
# Qt thread calls 'connect',   
# Python thread calls 'emit'.
# The slot corresponding to the emitted signal
# will be called in Qt's thread.
class SafeConnector:
    def __init__(self):
        self._rsock, self._wsock = socket.socketpair()
        self._queue = Queue.Queue()
        self._qt_object = QtCore.QObject()
        self._notifier = QtCore.QSocketNotifier(self._rsock.fileno(),
                                                QtCore.QSocketNotifier.Read)
        self._notifier.activated.connect(self._recv)

    def connect(self, signal, receiver):
        QtCore.QObject.connect(self._qt_object, signal, receiver)

    # should be called by Python thread
    def emit(self, signal, args):
        self._queue.put((signal, args))
        self._wsock.send('!')

    # happens in Qt's main thread
    def _recv(self):
        self._rsock.recv(1)
        signal, args = self._queue.get()
        self._qt_object.emit(signal, args)

class PythonThread(threading.Thread):
    def __init__(self, connector, *args, **kwargs):
        threading.Thread.__init__(self, *args, **kwargs)
        self.connector = connector
        self.daemon = True

    def emit_signal(self):
        self.connector.emit(QtCore.SIGNAL("test"), str(time.time()))

    def run(self):
        while True:
            time.sleep(1)
            self.emit_signal()

if __name__ == '__main__':
    app = QtGui.QApplication([])
    mainwin = QtGui.QMainWindow()
    label = QtGui.QLabel(mainwin)
    mainwin.setCentralWidget(label)

    connector = SafeConnector()
    python_thread = PythonThread(connector)
    connector.connect(QtCore.SIGNAL("test"), label.setText)
    python_thread.start()

    mainwin.show()
    app.exec_()