ruby - Ruby代码遍历两个数组simulataneoulsy

Question

如何同时在 ruby​​ 中迭代两个数组，我不想使用 for 循环。例如这是我的数组=

array 1=["a","b","c","d"]
array 2=[1,2,3,4]

Answer 1

例如，您可以像这样使用 zip 功能：

array1.zip(array2).each do |array1_var, array2_var|
 ## whatever you want to do with array_1var and array_2 var 
 end

Answer 2

您可以使用Array#zip（无需使用each，因为zip接受可选块）：

array1 = ["a","b","c","d"]
array2 = [1,2,3,4]

array1.zip(array2) do |a, b|
  p [a,b]
end

或者，Array#transpose：

[array1, array2].transpose.each do |a, b|
  p [a,b]
end

Answer 3

您可以zip将它们放在一起，然后使用each.

array1.zip(array2).each do |pair|
  p pair
end

Answer 4

如果两个数组的大小相同，您可以执行以下操作：

array1=["a","b","c","d"]
array2=[1,2,3,4]

for i in 0..arr1.length do
 //here you do what you want with array1[i] and array2[i]
end

Answer 5

假设两个数组的大小相同，您可以使用each_with_index第二个数组的索引来遍历它们：

array1.each_with_index do |item1, index|
  item2 = array2[index]
  # do something with item1, item2
end

像这样：

irb(main):007:0> array1.each_with_index do |item1, index|
irb(main):008:1*   item2 = array2[index]
irb(main):009:1>   puts item1, item2
irb(main):010:1> end
a
1
b
2
c
3
d
4

Answer 6

当两个数组的大小相同时，您可以执行以下操作：

array1=["a","b","c","d"]
array2=[1,2,3,4]

array2.each_index{|i| p "#{array2[i]},#{array1[i]} at location #{i}"}

# >> "1,a at location 0"
# >> "2,b at location 1"
# >> "3,c at location 2"
# >> "4,d at location 3"

如果有可能一个数组大于另一个数组，则larger_array#each_index必须调用。