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我需要做的是计算以下内容：

  1. 一个人在行中指定日期之前的日期出现在列表中的次数，并且 1 出现在第 7 列中。

  2. 一个人（第 8 列）在行中指定日期之前的日期出现在列表中的次数（请注意，它们是按时间顺序排序的。）

用一个例子来证明这一点可能更容易，来自 csv 的原始数据。

02/01/2005,Data,Class xpv,4,11yo+,4,1,George Smith
02/01/2005,Data,Class xpv,4,11yo+,4,2,Ted James
02/01/2005,Data,Class xpv,4,11yo+,4,3,Emma Lilly
02/01/2005,Data,Class xpv,4,11yo+,4,5,George Smith
02/01/2005,Data,Class tn2,4,10yo+,6,4,Tom Phillips
03/01/2005,Data,Class tn2,4,10yo+,6,2,Tom Phillips
03/01/2005,Data,Class tn2,4,10yo+,6,5,George Smith
03/01/2005,Data,Class tn2,4,10yo+,6,3,Tom Phillips
03/01/2005,Data,Class tn2,4,10yo+,6,1,Emma Lilly
03/01/2005,Data,Class tn2,4,10yo+,6,6,George Smith
04/01/2005,Data,Class tn2,4,10yo+,6,6,Ted James
04/01/2005,Data,Class tn2,4,10yo+,6,3,Tom Phillips
04/01/2005,Data,Class tn2,4,10yo+,6,2,George Smith
04/01/2005,Data,Class tn2,4,10yo+,6,4,George Smith
04/01/2005,Data,Class tn2,4,10yo+,6,1,George Smith
04/01/2005,Data,Class tn2,4,10yo+,6,5,Tom Phillips
05/01/2005,Data,Class 22zn,2,10yo+,5,3,Emma Lilly
05/01/2005,Data,Class 22zn,2,10yo+,5,1,Ted James
05/01/2005,Data,Class 22zn,2,10yo+,5,2,George Smith
05/01/2005,Data,Class 22zn,2,10yo+,5,4,Emma Lilly
05/01/2005,Data,Class 22zn,2,10yo+,5,5,Tom Phillips

由于遵循所描述的说明，我需要 csv 看起来像什么：

02/01/2005,Data,Class xpv,4,11yo+,4,1,George Smith,0,0
02/01/2005,Data,Class xpv,4,11yo+,4,2,Ted James,0,0
02/01/2005,Data,Class xpv,4,11yo+,4,3,Emma Lilly,0,0
02/01/2005,Data,Class xpv,4,11yo+,4,5,George Smith,0,0
02/01/2005,Data,Class tn2,4,10yo+,6,4,Tom Phillips,0,0
03/01/2005,Data,Class tn2,4,10yo+,6,2,Tom Phillips,0,0
03/01/2005,Data,Class tn2,4,10yo+,6,5,George Smith,1,2
03/01/2005,Data,Class tn2,4,10yo+,6,3,Tom Phillips,0,0
03/01/2005,Data,Class tn2,4,10yo+,6,1,Emma Lilly,0,1
03/01/2005,Data,Class tn2,4,10yo+,6,6,George Smith,1,2
04/01/2005,Data,Class tn2,4,10yo+,6,6,Ted James,0,1
04/01/2005,Data,Class tn2,4,10yo+,6,3,Tom Phillips,1,2
04/01/2005,Data,Class tn2,4,10yo+,6,2,George Smith,1,4
04/01/2005,Data,Class tn2,4,10yo+,6,4,George Smith,1,4
04/01/2005,Data,Class tn2,4,10yo+,6,1,George Smith,1,4
04/01/2005,Data,Class tn2,4,10yo+,6,5,Tom Phillips,0,3
05/01/2005,Data,Class 22zn,2,10yo+,5,3,Emma Lilly,1,2
05/01/2005,Data,Class 22zn,2,10yo+,5,1,Ted James,0,2
05/01/2005,Data,Class 22zn,2,10yo+,5,2,George Smith,2,7
05/01/2005,Data,Class 22zn,2,10yo+,5,4,Emma Lilly,1,2
05/01/2005,Data,Class 22zn,2,10yo+,5,5,Tom Phillips,0,5

因此，您可以看到在最后一行，Tom Phillips 在这一天之前的几天（第 10 列）出现了 5 次，并且在这 5 次出现中，第 7 列出现“1”的次数为零。

我的 csv 数据显然比这大得多，因此也将不胜感激有效的技术和建议。如果需要进一步澄清，请这样说，很难说这个例子是否可以理解。

4

1 回答 1

6

简单的一个：

import csv
import datetime
import copy
from collections import defaultdict

with open(r"C:\Temp\test.csv") as i, open(r"C:\Temp\resuls.csv", "wb") as o:
    rdr = csv.reader(i)
    wrt = csv.writer(o)

    data, currdate = defaultdict(lambda:[0, 0, 0, 0]), None
    for line in rdr:
        date, name = datetime.datetime.strptime(line[0], '%d/%m/%Y'), line[7]

        if date != currdate or not currdate:
            for v in data.itervalues(): v[:2] = v[2:]
            currdate = date

        wrt.writerow(line + data[name][:2])

        data[name][3] += 1
        if line[6] == "1": data[name][2] += 1

一个带深拷贝的：

import csv
import datetime
import copy
from collections import defaultdict

with open(r"C:\Temp\test.csv") as i, open(r"C:\Temp\resuls.csv", "wb") as o:
    rdr, wrt = csv.reader(i), csv.writer(o)

    curr, currdate = defaultdict(lambda:[0, 0]), None
    for line in rdr:
        date, name = datetime.datetime.strptime(line[0], '%d/%m/%Y'), line[7]

        if date != currdate or not currdate:
            prev = copy.deepcopy(curr)
            currdate = date

        wrt.writerow(line + prev[name])

        curr[name][1] += 1
        if line[6] == "1": curr[name][0] += 1
于 2013-09-29T20:14:32.667 回答