4

我正在尝试将字符串中的十六进制值转换为 ASCII 值和 UTF8 值。但是当我执行以下代码时，它会打印出与我输入的相同的十六进制值

string hexString = "68656c6c6f2c206d79206e616d6520697320796f752e";
System.Text.UTF8Encoding  encoding=new System.Text.UTF8Encoding();
byte[] dBytes = encoding.GetBytes(hexString);

//To get ASCII value of the hex string.
string ASCIIresult = System.Text.Encoding.ASCII.GetString(dBytes);
MessageBox.Show(ASCIIresult, "Showing value in ASCII");

//To get the UTF8 value of the hex string
string utf8result = System.Text.Encoding.UTF8.GetString(dBytes);
MessageBox.Show(utf8result, "Showing value in UTF8");
4

3 回答 3

5

由于您正在命名一个变量hexString，我假设该值已经编码为十六进制格式。

这意味着以下内容将不起作用：

string hexString = "68656c6c6f2c206d79206e616d6520697320796f752e";
System.Text.UTF8Encoding  encoding=new System.Text.UTF8Encoding();
byte[] dBytes = encoding.GetBytes(hexString);

这是因为您将已编码的字符串视为纯 UTF8 文本。

您可能缺少将十六进制编码字符串转换为字节数组的步骤。

您可以使用显示此功能的此 SO 帖子来执行此操作：

public static byte[] StringToByteArray(String hex)
{
  int NumberChars = hex.Length/2;
  byte[] bytes = new byte[NumberChars];
  using (var sr = new StringReader(hex))
  {
    for (int i = 0; i < NumberChars; i++)
      bytes[i] = 
        Convert.ToByte(new string(new char[2]{(char)sr.Read(), (char)sr.Read()}), 16);
  }
  return bytes;
}

所以，最终的结果是这样的：

byte[] dBytes = StringToByteArray(hexString);

//To get ASCII value of the hex string.
string ASCIIresult = System.Text.Encoding.ASCII.GetString(dBytes);
MessageBox.Show(ASCIIresult, "Showing value in ASCII");

//To get the UTF8 value of the hex string
string utf8result = System.Text.Encoding.UTF8.GetString(dBytes);
MessageBox.Show(utf8result, "Showing value in UTF8");
于 2013-09-26T10:09:19.340 回答
3

您应该首先将十六进制字符串转换为字节数组：

byte[] dBytes = Enumerable.Range(0, hexString.Length)
                 .Where(x => x % 2 == 0)
                 .Select(x => Convert.ToByte(hexString.Substring(x, 2), 16))
                 .ToArray();
于 2013-09-26T10:02:03.197 回答
0

我用这种方法来转换任何

public static string FromHex (string h) //Put your sequence of hex to convert to string.
{
    if (h.Length % 2 != 0) 
        throw new ArgumentException("The string " + nameof(h) + " is not a valid Hex.", nameof(h));
    char[] CharFromHex = new char[h.Length / 2];
    int j = 0;
    for (int i = 0; i < h.Length; i += 2)
    {
        string hexSubStr = h.Substring(i, 2);
        CharFromHex[j] = (char)Convert.ToInt32(hexSubStr, 16);
        j += 1;
    }
    StringBuilder str = new StringBuilder();
    str.Append(CharFromHex);
    return str.ToString();
}
于 2021-06-04T04:27:09.767 回答