php - 将数据显示到 html 表中

Question

我是 php 的新手程序员，我一直在寻找这个问题的解决方案。如果有人有想法请。发表您的答案，我感谢您解决这些问题的好主意。

在我的数据库表中，我有这样的数据：

在我的 php 页面中，我想使用 html 表以这种方式呈现。

谁能帮我做这件事？非常感谢……</p>

Answer 1

Try this:

$SQL = "select NAME, WEEK, STATUS from tblattendance order by NAME, SUBSTRING(WEEK,1,LENGTH(WEEK) - 2) ASC";

$data = $db->query($SQL);

$last_name = "";
echo '<table><tr><th>NAME</th><th>1st WEEK</th><th>2nd WEEK</th><th>3rd WEEK</th><th>4th WEEK</th>';
while($row = $data->fetch_assoc()){
    if($last_name != $row["NAME"]){
        $last_name = $row["NAME"];
        echo '</tr>';
        echo '<tr>';
        echo '<td>'.$row["NAME"].'</td>';
    }
    echo '<td>'.$row["STATUS"].'</td>';
}
echo '</tr></table>';

Answer 2

I think you are searching for the functionality of GROUP_CONCAT in mysql (docs). You would get something like:

SELECT name, GROUP_CONCAT( week ), GROUP_CONCAT( there )
FROM presence
GROUP BY name;

which will return the following results you can parse using explode() in php (docs):

Andrew  4th,1st,3rd,2nd     Present,Present,Present,Present
John    1st,4th,3rd,2nd     Absent,Present,Present,Present
Mark    2nd,3rd,1st,4th     Present,Present,Present,Present
Micheal 2nd,3rd,4th,1st     Absent,Absent,Absent,Present

On a side note: If you haven't settled on a database scheme yet, it might be better to use an int for the week number column, as it is more reliable when sorting and easier to manipulate.

Sqlfiddle: http://sqlfiddle.com/#!2/fc785/1

Answer 3

尝试这个 ：

$sql="select distinct name from tblattendance;";
$res=$mysqli->query($sql);
if($res){
   while($row=$res->fetch_assoc()){
       $name=$row['name'];
       $sql="select week, status from tblattendance where name='$name';";
       $res1=$mysqli->query($sql);
   }
}