我想在从 NSString 出现任何数字(1-9)之前删除所有出现的 0 对
if 000001234000 required 01234000
if 0000123400 required 123400
if 012340000 required 012340000
if 00000012 required 12
任何人都可以帮忙吗?谢谢。
我想在从 NSString 出现任何数字(1-9)之前删除所有出现的 0 对
if 000001234000 required 01234000
if 0000123400 required 123400
if 012340000 required 012340000
if 00000012 required 12
任何人都可以帮忙吗?谢谢。
也许不是最优雅的解决方案(但只修剪前导'00'):
- (NSString *)trimLeadingDoubleZerosFrom:(NSString *)str {
if (str.length > 1 ) {
if ([[str substringWithRange:NSMakeRange(0, 2)] isEqualToString:@"00"]) {
return [self trimLeadingDoubleZerosFrom:[str substringFromIndex:2]];
}
}
return str;
}
似乎适用于您的示例:
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"000001234000"]);// returns 01234000
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"0000123400"]); // returns 123400
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"012340000"]); // returns 012340000
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"00000012"]); // returns 12
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"12"]); // returns 12
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"02"]); // returns 02
NSLog(@"%@", [self trimLeadingDoubleZerosFrom:@"2"]); // returns 2
NSString* a = @"00000123";
while ([a hasPrefix:@"00"]) {
a = [a stringByReplacingCharactersInRange:NSMakeRange(0, 2) withString:@""];
}
NSString *MyString = @"00000123050060007";
NSString *NewString = [self RemovePairOfZero:MyString];
NSLog(@"OUTPUT:: %@", NewString);
- (NSString *)RemovePairOfZero:(NSString *)Param
{
if ([Param length] > 1 )
{
if ([[Param substringWithRange:NSMakeRange(0, 2)] isEqualToString:@"00"])
{
return [self RemovePairOfZero:[Param substringFromIndex:2]];
}
}
return Param;
}
//2013-09-24 13:15:58.527 Test[1584:907] OUTPUT:: 0123050060007
您可以尝试使用 stringByreplacingOccurancesOfString:@"00" withString:@""
NSString *s= @"00000123";
NSLog(@"%@",s);
s = [s stringByReplacingOccurrencesOfString:@"00" withString:@"."];
NSLog(@"%@",s);
试试这个。。
这可以通过简单地将@"00" 替换为@"" 来完成
NSString *string = @"00000123";
string = [string stringByReplacingOccurrencesOfString:@"00" withString:@""];
希望有帮助!