0

如果有答案，请提前抱歉，但我找不到我正在寻找的东西。

我目前有一个报告应用程序，它将数据结果从数据库查询返回到多维数组中。每个数组都是根据 id 字段构建的。我希望能够将数组合并到一个 id 相同的数组中。

例如这里是一个测试结果集。如您所见，id 为 1 的用户当前有两个结果。

Array
(

    [0] => Array
    (
        [AssessmentQuestion] => 1
        [AssessmentAnswer] => 0
        [id] => 1
    )

    [1] => Array
    (
        [AssessmentQuestion] => 2
        [AssessmentAnswer] => 2
        [id] => 1
    )
)

Array
(   
    [0] => Array    
    (
        [AssessmentQuestion] => 1
        [AssessmentAnswer] => 1
        [id] => 2
    )
)

如果 id 相同，我希望结果集看起来像这样。

Array
(
    [0] => Array
    (
        [AssessmentQuestion] => 1
        [AssessmentAnswer] => 0
        [AssessmentQuestion] => 2
        [AssessmentAnswer] => 2
        [id] => 1
    )
)

提前非常感谢。

这是我正在运行的查询。有一个自定义函数 ArrayFunctions::captureArrayFromResult()，这只是捕获数组结果。第一个查询只获取所有活动用户条目 id，然后每个 id 返回所有评估问题信息。

/**** COLLECT ALL ACTIVE USER ENTRY IDS ****/
$query = "SELECT DISTINCT ue.id
          FROM user_entry ue
          LEFT JOIN user_demographic_answers uda ON ue.id = uda.user_entry_id
          LEFT JOIN user_assessment_answers uaa ON ue.id = uaa.user_entry_id 
          WHERE $condition
          AND DATE(ue.datetime_finished) BETWEEN '{$this->reportDateRangeStart}' AND    '{$this->reportDateRangeEnd}'";
$results = db_Query($query);
$this->reportUserEntryID = ArrayFunctions::captureArrayFromResult($results, "id", "id");

foreach($this->reportUserEntryID as $userID)
{
    /**** COLLECT ASSESSMENT QUESTIONS ****/
    $query = SELECT DISTINCT uaa.question_id as 'AssessmentQuestion', uaa.answer_value as 'AssessmentAnswer', ue.id
          FROM user_assessment_answers uaa
          LEFT JOIN report_field_options rfo ON uaa.question_id = rfo.assessment_question_id
          LEFT JOIN user_entry ue ON uaa.user_entry_id = ue.id
          WHERE ($condition)
          AND DATE(ue.datetime_finished) BETWEEN '{$this->reportDateRangeStart}' AND '{$this->reportDateRangeEnd}'
          AND ue.id IN ($userID)
          ORDER BY uaa.question_id";
    $results = db_Query($query);
    $this->reportQuestionAssessmentAnswers = ArrayFunctions::captureArrayFromResult($results);
}
4

2 回答 2

0

您可以使用 foreach 循环来实现这一点：

$main_arr = array
(
     array
     (
         'AssessmentQuestion' => 1,
         'AssessmentAnswer' => 0,
         'id' => 1
     ),
     array
     (
         'AssessmentQuestion' => 2,
         'AssessmentAnswer' => 2,
         'id'=> 1
     ),
     array
     (
         'AssessmentQuestion' => 3,
         'AssessmentAnswer' => 4,
         'id' => 2
     ),
     array
     (
        'AssessmentQuestion' => 5,
        'AssessmentAnswer' => 6,
        'id'=> 1
     )
);

foreach ($main_arr as $arr) {
     $new_arr[$arr['id']]['id']  = $arr['id'];
     $new_arr[$arr['id']]['AssessmentQuestions'][] = $arr['AssessmentQuestion'];
     $new_arr[$arr['id']]['AssessmentAnswers'][] = $arr['AssessmentAnswer'];
}
var_dump($new_arr);
于 2013-09-20T14:21:27.480 回答
0

简短的回答：不可能按照您的要求做，因为数组键必须是唯一的。

我建议，在您的组合逻辑中，创建一个 and 数组AssesmentQuestions，AssesmentAnswers例如：

Array
(
    [0] => Array
    (
        [id] => 1,
        [AssesmentQuestions] => Array
        (
            [0] => 1,
            [1] => 2
        ),
        [AssesmentAnswers] => Array
        (
            [0] => 0,
            [1] => 2
        )
    )
)
于 2013-09-20T13:36:40.640 回答