11

我们正在对我们的控制器进行单元测试。我们已经成功地模拟了对 REST 服务层的调用，并验证了它确实是使用给定数据调用的。然而，现在我们想在我们的控制器中测试then承诺的执行会改变location.path：

控制器：

(function () {

    app.controller('registerController', ['$scope', '$location', '$ourRestWrapper', function ($scope, $location, $ourRestWrapper) {

    $scope.submitReg = function(){
        // test will execute this
        var promise = $ourRestWrapper.post('user/registration', $scope.register);

        promise.then(function(response) {    
                console.log("success!"); // test never hits here           
                $location.path("/");
        },
            function(error) {
                console.log("error!"); // test never hits here
                $location.path("/error");
            }
        );
    };

$ourRestWrapper.post(url,data)只是包装Restangular.all(url).post(data)..

我们的测试：

(function () {

    describe("controller: registerController", function() {

        var scope, location, restMock, controller, q, deferred;

        beforeEach(module("ourModule"));

        beforeEach(function() {
            restMock = {
                post: function(url, model) {
                    console.log("deferring...");
                    deferred = q.defer();    
                    return deferred.promise;
                }
            };
        });

        // init controller for test
        beforeEach(inject(function($controller, $rootScope, $ourRestWrapper, $location, $q){
            scope = $rootScope.$new();
            location = $location;
            q = $q;

            controller = $controller('registerController', {
                $scope: scope, $location: location, $ourRestWrapper: restMock});
        }));

    it('should call REST layer with registration request', function() {
        scope.register = {data:'test'};

        spyOn(restMock, 'post').andCallThrough();

        scope.submitReg();

        deferred.resolve();

        // successfull
        expect(restMock.post).toHaveBeenCalledWith('user/registration',scope.register);
        expect(restMock.post.calls.length).toEqual(1);
        // fail: Expected '' to be '/'.
        expect(location.path()).toBe('/');
    });

在我们的控制台中，我们看到“推迟……”并且前两个期望成功了。为什么它不会调用then块（即设置位置）？

4

1 回答 1

24

$rootscope从注入器获取对象时缓存对象并$rootScope.$apply()在deferred.resolve().

于 2013-09-20T14:34:37.583 回答