10

我是 iphone 开发新手，我想将CLLocationCoordinate2D对象存储到NSUserDefaults. 我在尝试

    [defaults setObject:location forKey:@"userLocation"];

但它给出了错误'将 CLLocationCoordinate2D 发送到不兼容类型 id 的参数'

那么如何CLLocationCoordinate2D存入NSUserDefaults呢？谢谢。

4

6 回答 6

34

正如pdrcabrod所说，

“默认对象必须是属性列表，即 , NSData, NSString, NSNumber, NSDate,NSArray或的实例NSDictionary。”

我用这个来存储，

    NSNumber *lat = [NSNumber numberWithDouble:location.latitude];
    NSNumber *lon = [NSNumber numberWithDouble:location.longitude];
    NSDictionary *userLocation=@{@"lat":lat,@"long":lon};

    [[NSUserDefaults standardUserDefaults] setObject:userLocation forKey:@"userLocation"];
    [[NSUserDefaults standardUserDefaults] synchronize];

并使用，

    NSDictionary *userLoc=[[NSUserDefaults standardUserDefaults] objectForKey:@"userLocation"];
    NSLog(@"lat %@",[userLoc objectForKey:@"lat"]);
    NSLog(@"long %@",[userLoc objectForKey:@"long"]);
于 2013-09-20T07:10:55.263 回答
15

这就是我要做的：

NSData *data = [NSData dataWithBytes:&coordinate length:sizeof(coordinate)];
[[NSUserDefaults standardUserDefaults] setObject:data forKey:@"key"];
[[NSUserDefaults standardUserDefaults] synchronize];

然后你可以像这样检索它：

NSData *data = [[NSUserDefaults standardUserDefaults] objectForKey:@"key"];
CLLocationCoordinate2D coordinate;
[data getBytes:&coordinate length:sizeof(coordinate)];
于 2013-09-20T07:09:46.127 回答
3

NSUserDefaults 类提供方便的方法来访问常见类型，例如浮点数、双精度数、整数、布尔值和 URL。默认对象必须是一个属性列表，即以下实例（或集合实例的组合）：NSData、NSString、NSNumber、NSDate、NSArray 或 NSDictionary。如果要存储任何其他类型的对象，通常应该将其归档以创建 NSData 的实例

请参阅：NSUserDefaults

于 2013-09-20T06:55:53.953 回答
3 
import CoreLocation

// Store an array of CLLocationCoordinate2D
func storeCoordinates(_ coordinates: [CLLocationCoordinate2D]) {
let locations = coordinates.map { coordinate -> CLLocation in
    return CLLocation(latitude: coordinate.latitude, longitude: coordinate.longitude)
}
let archived = NSKeyedArchiver.archivedData(withRootObject: locations)
UserDefaults.standard.set(archived, forKey: "coordinates")
UserDefaults.standard.synchronize()
}

// Return an array of CLLocationCoordinate2D
func loadCoordinates() -> [CLLocationCoordinate2D]? {
guard let archived = UserDefaults.standard.object(forKey: "coordinates") as? Data,
    let locations = NSKeyedUnarchiver.unarchiveObject(with: archived) as? [CLLocation] else {
        return nil
}

let coordinates = locations.map { location -> CLLocationCoordinate2D in
    return location.coordinate
}
        return coordinates
}

现在让我们测试一下实现：

let testCoordinates = [
CLLocationCoordinate2D(latitude: 0.123456789, longitude: 0.123456789),
CLLocationCoordinate2D(latitude: 1.123456789, longitude: 1.123456789),
CLLocationCoordinate2D(latitude: 2.123456789, longitude: 2.123456789)
]

self.storeCoordinates(testCoordinates)

let coordinates = loadCoordinates()
print(coordinates)
于 2018-06-08T12:02:01.817 回答
2

可以这样设置。。

CLLocationCoordinate2D coordinate; // need to set your coordinate here

[[defaults setObject:[NSString stringWithFormat:@"%g",coordinate.latitude] forKey:@"latitude"] ];
[[defaults setObject:[NSString stringWithFormat:@"%g",coordinate.longitude] forKey:@"longitude"] ];

我希望它有帮助。

于 2013-09-20T07:06:41.653 回答
1

正如其他人所说，首先将其转换为DictionaryorData对象，然后像往常一样保存它。在 Swift 中，我强烈推荐使用扩展。这是我所做的：

extension CLLocationCoordinate2D {

    private static let Lat = "lat"
    private static let Lon = "lon"

    typealias CLLocationDictionary = [String: CLLocationDegrees]

    var asDictionary: CLLocationDictionary {
        return [CLLocationCoordinate2D.Lat: self.latitude,
                CLLocationCoordinate2D.Lon: self.longitude]
    }

    init(dict: CLLocationDictionary) {
        self.init(latitude: dict[CLLocationCoordinate2D.Lat]!,
                  longitude: dict[CLLocationCoordinate2D.Lon]!)
    }

}
于 2017-06-04T07:43:22.400 回答