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我在 PHP 中创建了一个电子邮件类，但即使发布数据为空，它也总是返回成功。异常显然不起作用，我想知道为什么它也不发送任何电子邮件。这是代码：

<?php

class Contact
{
    private $toEmail = 'example@outlook.com', $subject = 'Personal Site - Contact';
    private $name, $email, $message;

public function __constructor(array $arr)
{
    if(!empty($arr['name']) && !empty($arr['email']) && !empty($arr['msg']))
    {
        $this->name = $this->ValidateName($arr['name']);
        $this->email = $this->ValidateEmail($arr['email']);
        $this->msg = $this->SanitizeMessage($arr['msg']);

        $this->SendMail($this->name, $this->email, $this->msg);
    }
    else
    {
        throw new Exception("Please fill all the required fields");
    }
}

private function ValidateName($name)
{
    if(ctype_alpha($name))
    {
        return $name;
    }
    else
    {
        return null;
    }
}

private function ValidateEmail($email)
{
    if(filter_var($email, FILTER_VALIDATE_EMAIL))
    {
        return $email;
    }
    else
    {
        return null;
    }
}

private function SanitizeMessage($msg)
{
    return htmlentities($msg);
}

private function SendMail($name, $email, $msg)
{
    $mailHeader = "From: " . $email . "\r\n"; 
    $mailHeader .= "Reply-To: " . $email . "\r\n"; 
    $mailHeader .= "Content-type: text/html; charset=iso-8859-1\r\n";

    $messageBody = "Name: " . $name . "";
    $messageBody .= "Email: " . $email . "";
    $messageBody .= "Comment: " . nl2br($msg) . "";

    if(mail($this->toEmail, $this->subject, $messageBody, $mailHeader))
    {
        return true;
    }
    else
    {
        throw new Exception('Message couldn\'t be sent');
    }
}
}

try
{
    $obj = new Contact($_POST);
}
catch(Exception $ex)
{
    echo json_encode($ex);
}

echo json_encode('Message was sent succesfully');

?>
4

1 回答 1

4

构造函数是__construct()，不是__constructor()。该函数永远不会被调用。
此外，避免在构造函数中执行操作、设置变量，这没关系，但实际上在创建新对象时发送邮件对于大多数开发人员来说是出乎意料的。

于 2013-09-19T19:42:15.800 回答