python - Find n words starting with capital letter before 2 words of capital letters (regex)

Question

I have written this regex but this is not working as expected.

((?:[A-Z][\w]+)?),[\s]([A-Z]{2})

Following are sample inputs.

Fort Worth, TX
This is Forth Worth, TX
We are looking for someone from Columbus, MS.

I expect City and State out of above string samples with regex in python but this is just no working as expected.

print re.findall('((?:[A-Z][\w]+){1,2}),[\s]([A-Z]{2})', input)

What am I missing?

score 1 · Accepted Answer

为什么不只是：

([A-Z][^,]+),\s([A-Z]{2})

或者，如果城市名称中只能包含单词字符和空格，则：

([A-Z][\w\s]+),\s([A-Z]{2})

score 1 · Accepted Answer

您可能想在您的城市名称组中添加一个空格字符，如下所示：

re.findall('((?:[A-Z][\w]+\s*){1,2}),[\s]([A-Z]{2})', input)

这将匹配一个大写拉丁字母，后跟一个或多个单词字符和零个或多个空格字符，所有这些都可能出现一两次，在第 1 组中捕获，后跟一个逗号、一个空格字符和两个大写拉丁字母，在第 2 组中捕获。

2 回答 2