4

我是一名大学生。现在，我正在做一个必须使用 LDAP 连接来验证登录过程中用户的用户名和密码的项目。所以，我的网站是使用 JSP 开发的。我试图解决代码错误，但我不能。我在上面犯了一些错误吗？

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@ page import="java.util.*" %>
<%@ page import="javax.naming.*" %>
<%@ page import="java.util.regex.*" %>
<%@ page import="javax.naming.directory.*" %>
<%@ page import="java.util.Hashtable.*" %>
<%@ page import="javax.naming.ldap.*" %>
<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>JSP Page</title>
    </head>
    <body>
        <%
            String username = request.getParameter("email");
String password = request.getParameter("password");
            Hashtable<String, String> env = new Hashtable<String, String>();
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, "ldap://ldap-pj.sit.kmutt.ac.th");
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, username);
env.put(Context.SECURITY_CREDENTIALS, password);

try {
            //Connect with ldap
            new InitialLdapContext(env, null);  

            //Connection succeeded
            System.out.println("Connection succeeded!");
        } catch (AuthenticationException e) {

            //Connection failed
            System.out.println("Connection failed!");
            e.printStackTrace();
        }  
%>
    </body>
</html>

我从运行代码中得到了这个错误消息。

HTTP 状态 500 -

类型异常报告

信息

描述 服务器遇到一个内部错误 () 阻止它完成这个请求。

例外

org.apache.jasper.JasperException：在第 33 行处理 JSP 页面 /ldap_checking.jsp 时发生异常

30: 31: try { 32: //连接 ldap 33: new InitialLdapContext(env, null); 34: 35: //连接成功 36: System.out.println("连接成功！");

堆栈跟踪：org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:455) org.apache.jasper.servlet.JspServlet.serviceJspFile( JspServlet.java:390) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 根本原因

javax.servlet.ServletException: javax.naming.InvalidNameException: [LDAP: 错误代码 34 - 无效 DN] org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:911) org.apache.jasper.runtime.PageContextImpl。 handlePageException(PageContextImpl.java:840) org.apache.jsp.ldap_005fchecking_jsp._jspService(ldap_005fchecking_jsp.java:212) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet。服务（HttpServlet.java:722）org.apache.jasper.servlet.JspServletWrapper.service（JspServletWrapper.java:432）org.apache.jasper.servlet.JspServlet.serviceJspFile（JspServlet.java:390）org.apache.jasper。 servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 根本原因

javax.naming.InvalidNameException：[LDAP：错误代码 34 - 无效 DN] com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:3028) com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:第2835章 不知道怎么办.java:193) com.sun.jndi.ldap.LdapCtxFactory.getUsingURLs(LdapCtxFactory.java:211) com.sun.jndi.ldap.LdapCtxFactory.getLdapCtxInstance(LdapCtxFactory.java:154) com.sun.jndi.ldap.LdapCtxFactory .getInitialContext(LdapCtxFactory.java:84) javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:684) javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:307) javax.naming.InitialContext.init(InitialContext.java :242) javax.naming.ldap。InitialLdapContext.(InitialLdapContext.java:153) org.apache.jsp.ldap_005fchecking_jsp._jspService(ldap_005fchecking_jsp.java:97) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet .service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390) org.apache.jasper .servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 注意 Apache Tomcat/7.0.27 日志中提供了根本原因的完整堆栈跟踪。70) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet. java:390) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 注意 根本原因的完整堆栈跟踪可在Apache Tomcat/7.0.27 日志。70) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet. java:390) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) 注意 根本原因的完整堆栈跟踪可在Apache Tomcat/7.0.27 日志。722) 注意 Apache Tomcat/7.0.27 日志中提供了根本原因的完整堆栈跟踪。722) 注意 Apache Tomcat/7.0.27 日志中提供了根本原因的完整堆栈跟踪。

Apache Tomcat/7.0.27

4

2 回答 2

7

这是重要的一行：javax.naming.InvalidNameException: [LDAP: error code 34 - invalid DN]

你可以看这里： https ://wiki.servicenow.com/index.php?title=LDAP_Error_Codes

34 是什么意思，但看起来您尝试使用的专有名称不正确。看起来您的主体可能格式不正确。请参阅 oracle 的本指南进行 ldap 身份验证： http ://docs.oracle.com/javase/jndi/tutorial/ldap/security/ldap.html

特别注意他们设置环境条目的这一部分：

env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, "cn=S. User, ou=NewHires, o=JNDITutorial");
env.put(Context.SECURITY_CREDENTIALS, "mysecret");
于 2013-09-16T15:46:22.340 回答
2

The "javax.naming.InvalidNameException: [LDAP: error code 34 - invalid DN] " in your stack trace is the key. Your LDAP server doesn't like the value you are sending it. I would suggest fully qualifying the user name, something like cn=username, ou=some_container, o=mycompany. The actual syntax will be driven by your LDAP server.

于 2013-09-16T15:49:16.213 回答