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我在使用以下代码时确实遇到了困难，我找不到将插入语句放置在该代码中的何处，它将插入来自 CTE 的返回值。

insert into ntm (num,comb,0,0,0,0,0,0,0,0,0,0,0,0)
with CTE as (
  SELECT a.ELM_NUM as num, 
         a.N_1 as N1,
         (trim('1.4*'||a.COMBO)||' + ' || '1.6*'||b.COMBO) as com2,
         b.ELM_NUM as num2 
    FROM NTM a cross join ntm b 
    where ((a.Combo='dead' and b.combo='live') or (a.Combo='dead' and b.combo='live')) and a.ELM_NUM=b.ELM_NUM) 

  select num, num2, trim(trim(com2)||' + '||trim(d.combo)), N1, 1.4*N1
    from CTE cross join ntm d
    where (d.elm_num = cte.num) and (position('X',combo)>0 or position('Y',combo)>0 )

FlameRobin 引擎引发的错误“令牌未知 - 第 1 行，第 27 0 列

CREATE TABLE NTM
(
ELM_NUM Integer NOT NULL,
COMBO Char(40) NOT NULL,
N_1 Double precision,
N_2 Double precision,
V2_1 Double precision,
V2_2 Double precision,
V3_1 Double precision,
V3_2 Double precision,
M2_1 Double precision,
M2_2 Double precision,
M3_1 Double precision,
M3_2 Double precision,
MT_1 Double precision,
MT_2 Double precision
);
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1 回答 1

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INSERT INTO <table> (<column>[, <column>]*)您可以通过在 select 语句（包括 ）之前添加来插入 select 语句的结果WITH。因此，如果您有疑问：

WITH a AS (
    SELECT 4 AS ID, 'Item 4' AS NAME FROM RDB$DATABASE
) 
SELECT ID, NAME 
FROM a

并且您想插入ITEMS包含列ID和的表中NAME：

INSERT INTO ITEMS (ID, NAME) 
WITH a AS (
    SELECT 4 AS ID, 'Item 4' AS NAME FROM RDB$DATABASE
) 
SELECT ID, NAME 
FROM a

这适用于 Firebird 2.5，但我认为它也适用于 Firebird 2.1。

根据您的编辑：

您的语法完全错误：无效：您在 table 中insert into ntm (num,comb,0,0,0,0,0,0,0,0,0,0,0,0)没有列，num并且指定为列名是非法的。您似乎将列列表与值列表混淆了。combntm0INSERT

an 的语法INSERT是：

INSERT INTO <object> [(col [, col …])]
{VALUES (<val> [, <val> …]) | <select_expr>}

你尝试使用类似的东西：

INSERT INTO <object> (<val> [, <val> …])
<select_expr>

假设您只想从您的选择中插入num(into ELM_NUM) 和trim(trim(com2)||' + '||trim(d.combo))(into COMBO) 列，您应该使用：

insert into ntm (ELM_NUM,COMBO)
with CTE as (
    SELECT a.ELM_NUM as num, 
         a.N_1 as N1,
         trim('1.4*'||a.COMBO)||' + ' || '1.6*'||b.COMBO as com2,
         b.ELM_NUM as num2 
    FROM NTM a cross join ntm b 
    where (a.Combo='dead' and b.combo='live' or a.Combo='dead' and b.combo='live') and a.ELM_NUM=b.ELM_NUM
) 
select num, trim(trim(com2)||' + '||trim(d.combo))
from CTE cross join ntm d
where d.elm_num = cte.num and (position('X',combo) > 0 or position('Y',combo) > 0)

请注意，我从选择中删除了其他列，因为您没有插入这些列（选择列表中的列数必须与插入列列表中的列数匹配）。

如果您希望剩余的列为 0，则需要将 a 添加DEFAULT 0到表定义中，或者您需要列出所有列并0在选择列表中为每个附加列添加一个值。

于 2013-09-14T07:53:44.627 回答