1

我在 HP ALM（以前的 Quality Center）中运行了两个查询：

查询一：

SELECT 
TEST.TS_NAME
FROM CYCLE
JOIN TESTCYCL ON (TESTCYCL.TC_CYCLE_ID = CYCLE.CY_CYCLE_ID)
JOIN TEST ON TEST.TS_TEST_ID = TESTCYCL.TC_TEST_ID)
WHERE CYCLE.CY_CYCLE_ID = 44451

这将返回 38 行，其中包含我要报告的所有测试名称。

查询 2：

SELECT 
STEP.ST_RUN_ID as "RunId" /*Test Step.Run No*/ ,
TEST.TS_NAME as "Test Name",
STEP.ST_STATUS as "Run Status",
STEP.ST_STEP_NAME as "Step Name",
CYCLE.CY_CYCLE as "TestSet",
CYCL_FOLD.CF_ITEM_NAME  as "Test Lab Folder Name"
FROM RUN, CYCL_FOLD, CYCLE, STEP, TEST
WHERE RUN.RN_CYCLE_ID = CYCLE.CY_CYCLE_ID
AND CYCLE.CY_FOLDER_ID = CYCL_FOLD.CF_ITEM_ID
AND CYCLE.CY_CYCLE_ID = 44451
AND STEP.ST_RUN_ID = RUN.RN_RUN_ID
AND RUN.RN_TEST_ID = TEST.TS_TEST_ID
AND RUN.RN_RUN_ID in (select MAX(RUN.RN_RUN_ID) FROM RUN
GROUP BY RN_TESTCYCLE_ID)

此查询返回所有测试以及各个步骤及其状态。MAX 语句返回该测试的最新运行。

运行测试时，会在 STEP 表中分配一个 RUN_ID。问题是如果一个测试没有运行，它不会有 RUN_ID，因此不会包含在结果中。

所以我创建了以下查询 3：

SELECT
STEP.ST_RUN_ID as "RunId" /*Test Step.Run No*/,
TEST.TS_NAME as "Test Name",
STEP.ST_STATUS as "Run Status",
STEP.ST_STEP_NAME as "Step Name",
CYCLE.CY_CYCLE as "TestSet",
CYCL_FOLD.CF_ITEM_NAME  as "Test Lab Folder Name" 
FROM RUN, CYCL_FOLD, CYCLE, STEP, TEST
    RIGHT JOIN (
          SELECT 
          TEST.TS_NAME
          FROM CYCLE
          JOIN TESTCYCL ON (TESTCYCL.TC_CYCLE_ID = CYCLE.CY_CYCLE_ID)
          JOIN TEST ON TEST.TS_TEST_ID = TESTCYCL.TC_TEST_ID)
          WHERE CYCLE.CY_CYCLE_ID = 44451) alltest 
          ON alltest.TS_NAME = TEST.TS_NAME
WHERE RUN.RN_CYCLE_ID = CYCLE.CY_CYCLE_ID
AND CYCLE.CY_FOLDER_ID = CYCL_FOLD.CF_ITEM_ID
AND STEP.ST_RUN_ID = RUN.RN_RUN_ID
AND RUN.RN_TEST_ID = TEST.TS_TEST_ID
AND RUN.RN_RUN_ID in (select MAX(RUN.RN_RUN_ID) FROM RUN GROUP BY rn_testcycl_id)

我想对所有测试进行 RIGHT JOIN 并填充记录了运行但它仍然没有返回 NULL 行的行。运行查询 2 或 3 之间没有区别。

4

2 回答 2

2

它没有返回行，因为where子句将它们过滤掉。

使用 ANSI 标准join语法（on子句）并将条件放在on子句中。结果是这样的：

SELECT s.ST_RUN_ID as "RunId" /*Test Step.Run No*/, t.TS_NAME as "Test Name",
       s.ST_STATUS as "Run Status", s.ST_STEP_NAME as "Step Name", c.CY_CYCLE as "TestSet",
       cf.CF_ITEM_NAME  as "Test Lab Folder Name" 
FROM RUN r join
     CYCL_FOLD cf
     on c.RN_CYCLE_ID = cf.CY_CYCLE_ID join
     CYCLE c
     on c.CY_FOLDER_ID = cf.CF_ITEM_ID join
     STEP s
     on s.ST_RUN_ID = r.RN_RUN_ID join
     TEST t
     on r.RN_TEST_ID = t.TS_TEST_ID right join
     (SELECT TEST.TS_NAME
      FROM CYCLE JOIN
           TESTCYCL
           ON TESTCYCL.TC_CYCLE_ID = CYCLE.CY_CYCLE_ID JOIN
           TEST
           ON TEST.TS_TEST_ID = TESTCYCL.TC_TEST_ID
      WHERE CYCLE.CY_CYCLE_ID = 44451
     ) alltest 
     ON alltest.TS_NAME = t.TS_NAME and
        r.RN_RUN_ID in (select MAX(RUN.RN_RUN_ID) FROM RUN GROUP BY rn_testcycl_id);
于 2013-09-13T11:07:31.540 回答
-3

如果要获取空值，请执行右外连接，而不是右连接。

于 2013-09-13T11:07:37.757 回答