这是问题：
编写一个交互式程序，为在一家小型化学零售店工作的 12 名员工（2 名员工是文员，1 名计算机操作员，6 名销售员，3 名助手）生成工资单。可以在必要时进行假设。工资单应显示员工编号、员工姓名、编号。当月的工作天数、工资单的生成日期、支付工资的月份、支付的所有细节、扣除额、总工资和净工资。
当我运行程序时，它说指针无效，即使我没有使用过指针，谁能告诉我这个程序有什么错误？
#include <time.h>
#include <stdlib.h>
#include <stdio.h>
#include <conio.h>
char name[30][30], designation[20[20], empid[12][12];
int i;
int n = 12;
int working_days = 27;
float basic[12], days_absent[12], days_present[12], gross_salary[20], pf[12], allowance[12], net[12];
void enter_details_of_employee();
void display();
void get_time();
void main()
{
int k;
printf("Enter 1 to enter employee details and 2 to display salary\n");
scanf("%d", &k);
if(k == 1)
{
enter_details_of_employee();
}
else if(k == 2)
{
display();
get_time();
}
else
{
printf("invalid choice");
}
}
void enter_details_of_employee ()
{
int choice;
int clerk_counter = 0, operator_counter = 0, salesman_counter = 0, helper_counter = 0, max = 0;
do {
printf("\n enter details of employees\n");
printf("enter employee name\n");
scanf("%c", &name);
printf("enter employee id\n");
scanf("%c", &empid);
printf("enter your choice for employee designation\n 1.clerk \n 2.computer operator\n 3. salesman\n 4.helper\n");
scanf("%d", &choice);
if (choice == 1)
{
if(clerk_counter == 2)
{
printf("sorry, you have already entered the details of all clerks\n");
}
else
{
designation = "clerk";
basic = 8000.00;
printf("enter no of days absent\n");
scanf("%d", &days_absent);
days_present = working_days - days_absent;
gross_salary = basic - ((days_absent / working_days) * basic);
pf = gross_salary*0.1;
allowance = gross_salary*0.55;
net = (gross - pf) + allowance;
clerk_counter++;
}
}
else if (choice == 2)
{
if(operator_counter == 1)
{
printf("sorry, you have already entered the details of all computer operators\n");
}
else
{
designation = "computer operator";
basic = 9000;
printf("enter no of days absent\n);
scanf("%d", &days_absent);
days_present = working_days - days_absent;
gross_salary = basic - ((days_absent / working_days) * basic);
pf = gross_salary*0.12;
allowance = gross_salary*0.75;
net = (gross - pf) + allowance;
operator_counter++;
}
}
else if (choice == 3)
{
if(salesman_counter == 6)
{
printf("sorry, you have already entered the details of all salesman\n");
}
else
{
designation = "salesman";
basic = 10000;
printf("enter no of days absent\n);
scanf("%d", &days_absent);
days_present = working_days - days_absent;
gross_salary = basic - ((days_absent / working_days) * basic);
pf = gross_salary*0.15;
allowance = gross_salary*0.95;
net = (gross - pf) + allowance;
salesman_counter++;
}
}
else if (choice == 4)
{
if(salesman_counter == 3)
{
printf("sorry, you have already entered the details of all helpers\n");
}
else
{
designation = "helper";
basic = 6500;
printf("enter no of days absent\n);
scanf("%d", &days_absent);
days_present = working_days - days_absent;
gross_salary = basic - ((days_absent / working_days) * basic);
pf = gross_salary*0.08;
allowance = gross_salary*0.45;
net = (gross - pf) + allowance;
helper_counter++;
}
}
else
{
printf("invalid choice");
}
}
while (max!=12);
}
void get_time()
{
time_t t = time(NULL);
struct tm tm = *localtime(&t);
printf("now: %d-%d-%d %d:%d:%d\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
}
void display()
{
printf("SALARY SLIP OF EMPLOYEES ";
printf("---------------------------------------------------------------------------------------------------");
printf("empid\t name\t days_absent\t days_present\t gross_salary\t PF\t allowance\t net");
printf("---------------------------------------------------------------------------------------------------");
for(i=0;i<n;i++)
{
printf(empid[i][i] name[i][i] basic[i] days_absent[i] days_present[i] gross_salary[i] pf[i] allowance[i] net);
}
}