如何让我的 Android 应用程序对返回按钮做出反应?
是否有高级 VCL 的 TApplicationEvents 来处理它,还是我需要在这里深入研究低级 Android 特定的东西?
现在,大多数演示应用程序都有一个屏幕后退按钮,可以返回到前一个屏幕。按下心理按钮似乎总是退出应用程序,在某些情况下会导致访问冲突。
如何让我的 Android 应用程序对返回按钮做出反应?
是否有高级 VCL 的 TApplicationEvents 来处理它,还是我需要在这里深入研究低级 Android 特定的东西?
现在,大多数演示应用程序都有一个屏幕后退按钮,可以返回到前一个屏幕。按下心理按钮似乎总是退出应用程序,在某些情况下会导致访问冲突。
在表单的OnKey...
事件中,Key
参数vkHardwareBack
在 Android 上。例如:
uses
FMX.Platform, FMX.VirtualKeyboard;
procedure TForm1.FormKeyUp(Sender: TObject; var Key: Word; var KeyChar: Char; Shift: TShiftState);
var
FService : IFMXVirtualKeyboardService;
begin
if Key = vkHardwareBack then
begin
TPlatformServices.Current.SupportsPlatformService(IFMXVirtualKeyboardService, IInterface(FService));
if (FService <> nil) and (vksVisible in FService.VirtualKeyBoardState) then
begin
// Back button pressed, keyboard visible, so do nothing...
end else
begin
// Back button pressed, keyboard not visible or not supported on this platform, lets exit the app...
if MessageDlg('Exit Application?', TMsgDlgType.mtConfirmation, [TMsgDlgBtn.mbOK, TMsgDlgBtn.mbCancel], -1) = mrOK then
begin
// Exit application here...
end else
begin
// They changed their mind, so ignore the Back button press...
Key := 0;
end;
end;
end
...
end;
供任何试图理解这一点的人将来参考。
if Key = vkHardwareBack then
begin
// your code here
key := 0;
end;
密钥:= 0;是阻止应用程序关闭的秘密..
这以 OnKeyUp 事件的形式出现
这是 Remy 答案的更新代码(与西雅图合作):
procedure TForm1.FormKeyUp(Sender: TObject; var Key: Word; var KeyChar: Char; Shift: TShiftState);
var
FService : IFMXVirtualKeyboardService;
begin
if Key = vkHardwareBack then
begin
TPlatformServices.Current.SupportsPlatformService(IFMXVirtualKeyboardService, IInterface(FService));
if (FService <> nil) and (TVirtualKeyboardState.Visible in FService.VirtualKeyBoardState) then
begin
// Back button pressed, keyboard visible, so do nothing...
end else
begin
Key := 0;
// Back button pressed, keyboard not visible or not supported on this platform, lets exit the app...
MessageDlg('Exit Application?', TMsgDlgType.mtConfirmation, [TMsgDlgBtn.mbOK, TMsgDlgBtn.mbCancel], -1, OnCloseDialog);
end;
end;
end;
procedure TForm1.OnCloseDialog(Sender: TObject; const AResult: TModalResult);
begin
if AResult = mrOK then
Close;
end;
返回上一个屏幕取决于您的应用程序设计。
如果您用于TTabControl
显示页面,则可以导航到上一个TTabItem
.
如果您用于TForms
显示页面,则必须使用Close()
关闭当前表单并返回上一个屏幕的过程。
尝试这个:
uses FMX.Platform,FMX.VirtualKeyboard,FMX.Helpers.Android;
procedure THeaderFooterForm.FormKeyUp(Sender: TObject; var Key: Word;
var KeyChar: Char; Shift: TShiftState);
var FService : IFMXVirtualKeyboardService;
begin
if Key = vkHardwareBack then
begin
TPlatformServices.Current.SupportsPlatformService(IFMXVirtualKeyboardService, IInterface(FService));
if (FService <> nil) and (vksVisible in FService.VirtualKeyBoardState) then
begin
// Back button pressed, keyboard visible, so do nothing...
end
else
begin
if MessageDlg('Exit Application?', TMsgDlgType.mtConfirmation, [TMsgDlgBtn.mbOK, TMsgDlgBtn.mbCancel], -1) = mrOK then
begin
// Exit application here...
SharedActivity.Finish;
end;
end;
end
else
// Menu button pressed
if Key = sgiUpRightLong then
begin
showmessage('Menu button pressed');
end;
end;
GetIt Package Manager ( https://getitnow.embarcadero.com/card-view-wizard/ ) 提供的 Card View Wizard 1.0 具有此代码(我只更改了普通的“// do nothing comment”以更具描述性)仅当一组启动卡序列仍然或返回第一张卡时退出应用程序,否则导航到上一张卡:
procedure TMainForm.FormKeyUp(Sender: TObject; var Key: Word; var KeyChar: Char;
Shift: TShiftState);
var
FService : IFMXVirtualKeyboardService;
begin
if Key = vkHardwareBack then
begin
TPlatformServices.Current.SupportsPlatformService(IFMXVirtualKeyboardService, IInterface(FService));
if (FService <> nil) and (TVirtualKeyboardState.Visible in FService.VirtualKeyBoardState) then
begin
// Back button pressed, keyboard visible, so do nothing...
end
else
begin
if WizardTabControl.ActiveTab <> TabItem1 then
begin
WizardTabControl.SetActiveTabWithTransitionAsync(WizardTabControl.Tabs[WizardTabControl.TabIndex-1],TTabTransition.Slide,TTabTransitionDirection.Reversed,nil);
Key := 0;
end;
end;
end
end;
当然,正如其他答案所示,您也可以提示用户,以防他们不小心尝试退出应用程序,不要继续。