5

我收到错误“将 nvarchar 值 '23,24,3,45,91' 转换为数据类型 int 时转换失败。” 该错误似乎发生在 ON 子句上。E.ID 是一个整数字段，而 F.LegalIssue 是一个用逗号分隔的整数的 varchar 字段。下面是出现该错误的代码。

SELECT F.[FDTitle], E.PrimaryOpID as [FD Primary OP ID], F.County as [FD County], F.Status as [FD Status], F.IssueDate as [FD Date]
FROM [dbo].[tbl_FinalDetMain] F
LEFT OUTER JOIN [dbo].[tbl_lk_Exemptions_FD] E ON E.ID = F.LegalIssue
WHERE F.[FDNbr] = '2013-0041'

我已经为 on 子句尝试了下面的代码，但它只返回一个整数值，而不是整个整数字符串。

E.ID = cast(LEFT(F.LegalIssue,PATINDEX('%[^0-9]%',F.LegalIssue)-1) as int)

结果应包括五个用逗号分隔的整数。

4

3 回答 3

9

如果LegalIssue包含一串以逗号分隔的数字，那么您确实需要一个关联表。缺少这一点，这是一种方便（但不是有效）的连接方式：

SELECT F.[FDTitle], E.PrimaryOpID as [FD Primary OP ID], F.County as [FD County],
       F.Status as [FD Status], F.IssueDate as [FD Date]
FROM [dbo].[tbl_FinalDetMain] F LEFT OUTER JOIN
      [dbo].[tbl_lk_Exemptions_FD] E
      ON ','+F.LegalIssue+',' like '%,'cast(E.ID as varchar(255))+',%'
WHERE F.[FDNbr] = '2013-0041';

这会在列表前添加和后添加逗号以避免冲突，例如在“1,100,1000”中查找“10”。

于 2013-09-11T14:55:05.290 回答
3

使用 xml 数据类型，您可以像这样将字符串分解为整数。我会说用户定义函数的好人选:-)

declare @test varchar(max)

set @test = '1,2,3,4,5'

select 
     T2.item.value('(./text())[1]','int') 
from
     (select convert(xml,'<items><t>'+replace(@test,',','</t><t>')+'</t></items>') as xmldoc)
as xmltable
     CROSS APPLY xmltable.xmldoc.nodes('/items/t') as T2(item)
于 2013-09-11T15:34:18.383 回答
1

您要么必须将 F.LegalIssue 标准化为多行，要么必须使用 LIKE

就像是

    CAST(E.ID A VARCHAR(50)) = F.LegalIssue
OR  F.LegalIssue LIKE CAST(E.ID A VARCHAR(50)) + ',%'
OR  '%,' + F.LegalIssue LIKE CAST(E.ID A VARCHAR(50)) + ',%'
OR  '%,' + F.LegalIssue LIKE CAST(E.ID A VARCHAR(50))

如您所见，表的实际设计是问题所在。您应该避免使用您当前拥有的设计，并选择一个1 to many或many to many设计。

这是一个演示如何使用递归 CTE 展平值

SQL 小提琴演示

创建测试表和数据

CREATE TABLE Tada(
  ID INT,
  SomeCommaString VARCHAR(50)
  )
INSERT INTO Tada Values (1, '10'),(2,'5,6,12,16')

把桌子弄平

;WITH Vals AS (
  SELECT 
      ID,
      CASE
          WHEN CHARINDEX(',',SomeCommaString) = 0
            THEN SomeCommaString
          WHEN CHARINDEX(',',SomeCommaString) > 0
            THEN LEFT(SomeCommaString,CHARINDEX(',',SomeCommaString) - 1)
      END Val,

      CASE
          WHEN CHARINDEX(',',SomeCommaString) > 0
            THEN RIGHT(SomeCommaString,LEN(SomeCommaString) - CHARINDEX(',',SomeCommaString))
          ELSE NULL
      END Remainder
  FROM Tada
  UNION ALL
  SELECT 
      ID,
      CASE
          WHEN CHARINDEX(',',Remainder) = 0
            THEN Remainder
          WHEN CHARINDEX(',',Remainder) > 0
            THEN LEFT(Remainder,CHARINDEX(',',Remainder) - 1)
      END Val,

      CASE
          WHEN CHARINDEX(',',Remainder) > 0
            THEN RIGHT(Remainder,LEN(Remainder) - CHARINDEX(',',Remainder))
          ELSE NULL
      END Remainder

  FROM Vals
  WHERE Remainder IS NOT NULL
)
SELECT ID, Val
FROM Vals
于 2013-09-11T14:50:30.260 回答